我的代码现在看起来像这样(请参阅下面的更新代码):
BufferedReader infile = new BufferedReader(new FileReader("file.txt"));
String line;
int i = 0;
while ((line = infile.readLine()) != null) {
String first, second, last;
//Split line into first, second and last (word)
//Do something with words (no help needed)
i++;
}
这是完整的file.txt:
Allegrettho Albert 0111-27543 Brio Britta 0113-45771 Cresendo Crister 0111-27440 Dacapo Dan 0111-90519 Dolce Dolly 0116-31418 Espressivo Eskil 0116-19042 Fortissimo Folke 0118-37547 Galanto Gunnel 0112-61805 Glissando Gloria 0112-43918 Grazioso Grace 0112-43509 Hysterico Hilding 0119-71296 Interludio Inga 0116-22709 Jubilato Johan 0111-47678 Kverulando Kajsa 0119-34995 Legato Lasse 0116-26995 Majestoso Maja 0116-80308 Marcato Maria 0113-25788 Molto Maja 0117-91490 Nontroppo Maistro 0119-12663 Obligato Osvald 0112-75541 Parlando Palle 0112-84460 Piano Pia 0111-10729 Portato Putte 0112-61412 Presto Pelle 0113-54895 Ritardando Rita 0117-20295 Staccato Stina 0112-12107 Subito Sune 0111-37574 Tempo Kalle 0114-95968 Unisono Uno 0113-16714 Virtuoso Vilhelm 0114-10931 Xelerando Axel 0113-89124
@Pshemo的新代码建议:
public String load() {
try {
Scanner scanner = new Scanner(new File("reg.txt"));
while (scanner.hasNextLine()) {
String firstname = scanner.next();
String lastname = scanner.next();
String number = scanner.next();
list.add(new Entry(firstname, lastname, number));
}
msg = "The file reg.txt has been opened";
return msg;
} catch (NumberFormatException ne) {
msg = ("Can't find reg.txt");
return msg;
} catch (IOException ie) {
msg = ("Can't find reg.txt");
return msg;
}
}
我收到多个错误,出了什么问题?
答案 0 :(得分:1)
假设每一行总是包含三个单词而不是分割,那么每行只需使用Scanner
方法next
三次。
Scanner scanner = new Scanner(new File("file.txt"));
int i = 0;
while (scanner.hasNextLine()) {
String first = scanner.next();
String second = scanner.next();
String last = scanner.next();
//System.out.println(first+": "+second+": "+last);
i++;
}
答案 1 :(得分:0)
line.split("\\s+"); // don't use " ". use "\\s+" for more than one whitespace
答案 2 :(得分:0)
假设该行有3个以上的单词,请使用split(delimiter)
方法:
String line = ...;
String[] parts = line.split("\\s+"); // Assuming words are separated by whitespaces, use another if required
然后你可以分别访问第一个,第二个和最后一个:
String first = parts[0];
String second = parts[1];
String last = parts[parts.length() - 1];
请记住,索引从0开始。
答案 3 :(得分:0)
String []parts=line.split("\\s+");
System.out.println(parts[0]);
System.out.println(parts[1]);
System.out.println(parts[parts.length-1]);