我在while循环中遇到EOF的问题。它似乎只是在输入EOF时结束，而是这样做......
如何修复它并让while循环停止并继续前进。感谢。
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <limits.h>
void findLargestandSmallest(int integer, int* largest, int* smallest, int* average, int count);
int main(void)
{
//Local Declaration
int integer;
int largest;
int smallest;
int average;
int count; // number count
//Starting statemnets
smallest = INT_MAX;
largest = INT_MIN;
count = 0;
// Starting prompts
printf("\nHello this program will take in intagers and print");
printf("\nout the largest, smallest and avarage of integers");
printf("\nenterd int.");
printf("\nPlease enter in a integer ");
while (scanf("%d", &integer) != EOF)
{
if (integer != EOF)
{
count++;
findLargestandSmallest(integer, &largest, &smallest, &average, count);
}
else
{
printf("\n \n");
}
}
printf("\nThe largest number entered is %d and the smallest", largest);
printf("\nwas %d and the average of all the numbers is %d\n", smallest, average);
return 0;
}
void findLargestandSmallest(int integer, int *largest, int *smallest, int *average, int count)
{
int x; // just a holder variable
// finds average
x = 0;
x += integer;
*average = (x / count);
// Finds smallest and largest
if (integer <= *smallest)
{
*smallest = integer;
}
if (integer >= *largest)
{
*largest = integer;
}
printf("Enter another integer or <EOF> to quit ");
return;
}
[1]: http://i.stack.imgur.com/P0307.png
更新：我发现我做错了什么。这很简单。在while循环中while(scanf("%d", &integer) != EOF)不要像那样设置它，但是像这样(scanf("%d", &integer)) EOF被理解。要在DOS中简单地调用它，请在上次输入时使用“Ctrl + Z”。即“数字^ Z”是使用“Ctrl + Z”后的样子。对于遇到此问题的任何其他人来说，这里有更好的工作代码。
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <limits.h>
void findLargestandSmallest(int integer, int* largest, int* smallest);
int main(void)
{
//Local Declaration
int integer;
int largest;
int smallest;
int average;
int sum;
int count;
//Starting statemnets
smallest = INT_MAX;
largest = INT_MIN;
count = 0;
sum = 0;
// Starting prompts
printf("\n--------------------------------------------------------");
printf("\n- Hello, this program will take in intagers and print -");
printf("\n- out the largest, smallest, and avarage of the -");
printf("\n- integers enterd. -");
printf("\n- NOTE: To quit: use \"Ctrl+Z\" on the last integer -");
printf("\n- you enter i.e \"number^z\" -");
printf("\n--------------------------------------------------------\n");
printf("\nEnter integers\n");
// Finds largest and smallest number
while (scanf("%d", &integer))
{
sum += integer;
count++;
findLargestandSmallest(integer, &largest, &smallest);
}
// Finds average
count--;
average = (sum / count);
// End prompts
printf("\n--------------------------------------------------------");
printf("\nThe largest number entered was %d, the smallest", largest);
printf("\nwas %d, and the average of all the numbers is %d.", smallest, average);
printf("\n--------------------------------------------------------");
printf("\nGoodbye\n");
return 0;
}
void findLargestandSmallest(int integer, int *largest, int *smallest)
{
if (integer < *smallest)
{
*smallest = integer;
}
if (integer > *largest)
{
*largest = integer;
}
return;
}
答案 0 :(得分：1)
scanf返回成功转换的元素数。如果它无法转换，则返回0. EOF仅返回文件结尾（在Unix上为Control-D）。
因此，您应该修改程序以保存scanf的返回值，然后分别测试0和EOF。
将integer变量与EOF进行比较也没有意义，因为您可能知道EOF的所有内容都是负整数。阅读scanf手册页，了解它的作用以及它在何时何地返回。那就解决了这个谜题。 ： - ）
好的，还有一些提示。你能理解这个吗？
for (;;) {
int successfully_converted = scanf("%d", &integer);
if (successfully_converted == EOF) {
/* Do something when the user is tired of typing. */
puts("Thank you for an enjoyable game.\n");
exit(0);
} else if (successfully_converted == 0) {
puts("This didn't look like an integer\n");
exit(1);
} else {
/* Do something with integer. */
}
}
答案 1 :(得分：0)
您没有将整数值与EOF进行比较 。您正在将scanf结果与EOF进行比较。 在这里每次输入1个值时，scanf结果将为1。
所以evrrytime while循环条件失败并且生成无限循环。 此外，如果你EOF那么你将输入什么字符来结束循环??? 所以不应该使用EOF。
所以我建议你使用do while loop
DO
{
的scanf（ “％d”，＆安培;整数）;
...
... printf（“输入1继续”）;
的scanf（ “％d”，＆安培;检查）;
} while（check == 1）;
答案 2 :(得分：0)
针对EOF，0和1测试scanf()的结果。
int cnt;
while ((cnt = scanf("%d", &integer)) == 1) {
count++;
findLargestandSmallest(integer, &largest, &smallest, &average, count);
}
if (cnt == 0) {
printf("Something other than an integer was entered.\n");
}
else if (cnt == EOF) {
printf("EOF or I/O Error occurred.\n");
}
// Add the following for debug if desired
else {
printf("Should _never get here!\n");
}
...
答案 3 :(得分：0)
更新：我发现我做错了什么。这很简单。在while循环while（scanf（“％d”，＆amp;整数）！= EOF）不要像那样设置它（scanf（“％d”，＆amp; integer））EOF被理解。要在DOS中简单地调用它，请在上次输入时使用“Ctrl + Z”。即“数字^ Z”是使用“Ctrl + Z”后的样子。对于遇到此问题的任何其他人来说，这里有更好的工作代码。
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <limits.h>
void findLargestandSmallest(int integer, int* largest, int* smallest);
int main(void)
{
//Local Declaration
int integer;
int largest;
int smallest;
int average;
int sum;
int count;
//Starting statemnets
smallest = INT_MAX;
largest = INT_MIN;
count = 0;
sum = 0;
// Starting prompts
printf("\n--------------------------------------------------------");
printf("\n- Hello, this program will take in intagers and print -");
printf("\n- out the largest, smallest, and avarage of the -");
printf("\n- integers enterd. -");
printf("\n- NOTE: To quit: use \"Ctrl+Z\" on the last integer -");
printf("\n- you enter i.e \"number^z\" -");
printf("\n--------------------------------------------------------\n");
printf("\nEnter integers\n");
// Finds largest and smallest number
while (scanf("%d", &integer))
{
sum += integer;
count++;
findLargestandSmallest(integer, &largest, &smallest);
}
// Finds average
count--;
average = (sum / count);
// End prompts
printf("\n--------------------------------------------------------");
printf("\nThe largest number entered was %d, the smallest", largest);
printf("\nwas %d, and the average of all the numbers is %d.", smallest, average);
printf("\n--------------------------------------------------------");
printf("\nGoodbye\n");
return 0;
}
void findLargestandSmallest(int integer, int *largest, int *smallest)
{
if (integer < *smallest)
{
*smallest = integer;
}
if (integer > *largest)
{
*largest = integer;
}
return;
}