使用Yii创建多级菜单

Question

如何查询yii中多级菜单的情况？

例如，我有一个这样的表：

menu_name会跟随它parrent_id，因此会形成hierarchical菜单

如何在布局上使用Yii，以便输出为上面的html

我的代码：

<?php
Yii::import('zii.widgets.CMenu', true);

class ActiveMenu extends CMenu
{
    public function init(){

    $criteria = new CDbCriteria;
    $criteria->condition='published=:idpub AND menu_controller=:menu';
    $criteria->params=array(':idpub'=>1, ':menu'=>'#');

    $items = Menu::model()->findAll($criteria);

    echo "<ul id='yw1' class='nav'>";

        foreach ($items as $item)
        {
            echo "<li class='dropdown'>
                    <a href=".$item->menu_controller." data-toggle='dropdown' class='dropdown-toggle'>
                    <i class='icon-white icon-list'></i>".$item->menu_name."<b class='caret'></b></a>
                </li>";
        }

        echo "</ul>";

        parent::init();
    }
}

但在上面的代码中我只得到parents data。我如何循环以在每个父母菜单中获取childs data包括此html代码：

<ul id="yw1" class="nav">
    <li><a href="/app/home.html"><span class="icon-white icon-tasks"></span> Home</a></li>

    <li class="dropdown">
        <a href="#" data-toggle="dropdown" class="dropdown-toggle">
        <i class="icon-white icon-list"></i>Master<b class="caret"></b></a>
        <ul class="dropdown-menu">
            <li><a href="expedition"><span class="icon-bar icon-list"></span> Expedition</a></li>
        </ul>
        <ul class="dropdown-menu">
            <li><a href="partner"><span class="icon-bar icon-list"></span> Partner</a></li>
        </ul>
        <ul class="dropdown-menu">
            <li><a href="user"><span class="icon-bar icon-list"></span> User</a></li>
        </ul>
    </li>

    <li class="dropdown">
        <a href="#" data-toggle="dropdown" class="dropdown-toggle">
        <i class="icon-white icon-list"></i>Transaction<b class="caret"></b></a>
        <ul class="dropdown-menu">
            <li><a href="processin"><span class="icon-bar icon-list"></span> Process In</a></li>
        </ul>
        <ul class="dropdown-menu">
            <li><a href="processout"><span class="icon-bar icon-list"></span> Process Out</a></li>
        </ul>
        etc ....
        etc ....
        etc ....
    </li>
</ul>

由于

Answer 1

您可以创建一个递归函数来循环您的孩子，就像这样

<?php
    class ActiveMenu extends CMenu
    {
        public function init(){
            $this->renderChilds();
        }

        protected function getChilds($parent_id)
        {
            $criteria = new CDbCriteria;
            $criteria->condition='published=:idpub AND menu_controller=:menu AND parent_id = :parent';
            $criteria->params=array(':idpub'=>1, ':menu'=>'#', ':parent'=>$parent_id);
            $items = Menu::model()->findAll($criteria);
            return $items;
        }            

        public function renderChilds($parent_id=0, $class='nav')
        {
             $items = $this->getChilds($parent_id);
             if (!empty($items))
             {
                 echo "<ul class='$class'>";
                 foreach ($items as $item)
                 {
                     echo "<li class='dropdown'>
                     <a href=".$item->menu_controller." data-toggle='dropdown' class='dropdown-toggle'>
                     <i class='icon-white icon-list'></i>".$item->menu_name."<b class='caret'></b></a>";
                     $this->renderChilds($item->id, 'dropdown-menu');                
                     echo "</li>";
                 }
                 echo "</ul>";
             }
         }

         ...
     }