Question

我正在尝试将base64_encoded xml字符串转换为我无法控制的c＃WebAPI。我可以成功地cURL字符串，但它不被API接受。

记录输出显示cURL正在从base64字符串中剥离+字符，我认为这是问题所在。

我的代码是：

$username = "username";
$password = "$23hrlkbl";
$xml = "<Envelope><Header><User>".$username."</User><Password>".$password."</Password></Header></Envelope>";

$passThru = "https://api.domain.com/SignIn.aspx?passthruUrl=/Management/Api/DataEnrichment/GetAddresses/?buildingNumber=1%26streetName=Nightingale%20Road%26postcode=L12%200QN
$post_packet_data = 'XMLdataPacket='.urlencode(base64_encode($xml));

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $passThru);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $post_packet_data);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt($ch, CURLOPT_HEADER, 1);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);

$response = curl_exec ($ch);
curl_close($ch);
print_r($response);

通过html表单将以下字符串（非urlencoded $ post_packet_data）发布到$ passThru地址可以成功运行

XMLdataPacket=PEVudmVsb3BlPjxIZWFkZXI+PFVzZXI+dXNlcm5hbWU8L1VzZXI+PFBhc3N3b3JkPiQyM2hybGtibDwvUGFzc3dvcmQ+PC9IZWFkZXI+PC9FbnZlbG9wZT4=

但是，当通过cURL发布相同的字符串时，会发送以下内容并且不被接受

XMLdataPacket=PEVudmVsb3BlPjxIZWFkZXI PFVzZXI dXNlcm5hbWU8L1VzZXI PFBhc3N3b3JkPiQyM2hybGtibDwvUGFzc3dvcmQ PC9IZWFkZXI PC9FbnZlbG9wZT4=

更新

在与API的开发人员交谈之后，他们已经确认请求现在以正确的格式进入，但认为由于发送了错误的标头而未对呼叫进行处理。他们给我发了一个工作电话的标题，这是他们用fiddler获得的：

POST https://api.domain.com/SignIn.aspx?passthruUrl=/Management/Api/DataEnrichment/GetAddresses/?buildingNumber=1%26streetName=Nightingale%20Road%26postcode=L12%200QN HTTP/1.1
Host: test.domain.com
Connection: keep-alive
Content-Length: 164
Cache-Control: max-age=0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8
Origin: null
User-Agent: Mozilla/5.0 (Windows NT 6.3; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/33.0.1750.146 Safari/537.36
Content-Type: application/x-www-form-urlencoded
Accept-Encoding: gzip,deflate,sdch
Accept-Language: en-GB,en-US;q=0.8,en;q=0.6
Cookie: ASP.NET_SessionId=uzwfjq3zojao3l5fw141l453

XMLdataPacket=PEVudmVsb3BlPjxIZWFkZXI%2BPFVzZXI+dXNlcm5hbWU8L1VzZXI%2BPFBhc3N3b3JkPiQyM2hybGtibDwvUGFzc3dvcmQ%2BPC9IZWFkZXI%2BPC9FbnZlbG9wZT4%3D

如何修改cURL调用的标头以复制上述内容。目前再次使用fiddler，cURL调用标题显示如下：

GET http://test.domain.com/test_call.php HTTP/1.1
Host: test.domain.com
User-Agent: Mozilla/5.0 (Windows NT 6.3; WOW64; rv:27.0) Gecko/20100101 Firefox/27.0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Language: en-gb,en;q=0.5
Accept-Encoding: gzip, deflate
Cookie: CAKEPHP=g22d7kf7qs8b1v02uui2mnop30
Authorization: Basic bmV0aG91c2VwcmljZXMxOnRlbXAxODkx
Connection: keep-alive
Cache-Control: max-age=0

数据在api端收到POST作为但是卷曲头根据上面的GET进行

Answer 1

尝试使用rawurlencode（）而不是urlencode（） - 它使用'％20'编码空格字符，而不是使用'+'字符。

cURL base64_encode XML

1 个答案: