sql server触发从连接表中提取数据

Question

我想在与其他表链接的表上创建插入更新和删除的触发器 当发生上述任何一种情况时，触发器应从插入的表中提取一个值，并从连接的表中提取其他值 并将这些插入另一个表

这是一个简化的答案，但我在员工加入时收到错误说多部分标识符无法绑定

Create TRIGGER triggertest
ON salary 
FOR INSERT
AS 
BEGIN


DECLARE @salary int
DECLARE @firstName int


SELECT @salary = i.salary, @firstName =employee.firstName
FROM inserted i 


        INNER JOIN employee  ON
             i.employeeID = emplopyee.employeeID 
        INNER JOIN deleted d ON  i.salaryID = d.salaryID 





    INSERT INTO testTAble
    (employeeFirstName,EmployeeSalary)
    select @firstName ,@salary 

END

Answer 1

您的要求可以是：

插入

CREATE TRIGGER triggertestI
ON salary 
FOR INSERT
AS 
BEGIN
    INSERT INTO testTAble
    (employeeFirstName,EmployeeSalary)
    SELECT i.salary, employee.firstName
    FROM inserted i 
    INNER JOIN employee
    ON i.employeeID = employee.employeeID 
END

<强>更新

CREATE TRIGGER triggertestU
ON salary 
FOR UPDATE
AS 
BEGIN
    UPDATE testTAble
    SET EmployeeSalary = 
    (SELECT i.salary
    FROM inserted i 
    INNER JOIN employee
    ON i.employeeID = employee.employeeID
    where i.employeeID = testTable.employeeID)
END

删除

CREATE TRIGGER triggertestD
ON salary 
FOR DELETE
AS 
BEGIN
    DELETE FROM testTAble
    WHERE employeeID in (
    SELECT i.employeeID
    FROM deleted i 
    INNER JOIN employee
    ON i.employeeID = employee.employeeID
    where i.employeeID = testTable.employeeID)
END

P.S。我认为，在您的查询中，错误是：emplopyee（您在表名员工中添加了意外的非p）

Answer 2

错误：

i.employeeID = emplopyee.employeeID 

您的'p'中添加了

额外emplopyee.employeeID。 emplopyee必须为employee