我在Selenium webdriver中运行代码,每当找不到元素时,它就会捕获。但我希望java在跳过该元素后继续执行。
import java.util.regex.Pattern;
import java.util.concurrent.TimeUnit;
import net.sourceforge.htmlunit.corejs.javascript.ast.LabeledStatement;
import org.junit.*;
import static org.junit.Assert.*;
import static org.hamcrest.CoreMatchers.*;
import org.openqa.selenium.*;
import org.openqa.selenium.firefox.FirefoxDriver;
import org.openqa.selenium.support.ui.Select;
import com.gargoylesoftware.htmlunit.ElementNotFoundException;
import com.google.protobuf.DescriptorProtos.FieldDescriptorProto.Label;
import com.sun.org.apache.bcel.internal.generic.GOTO;
public class try_zencart {
private WebDriver driver;
private String baseUrl;
private boolean acceptNextAlert = true;
private StringBuffer verificationErrors = new StringBuffer();
@Before
public void setUp() throws Exception {
driver = new FirefoxDriver();
baseUrl = "http://ipadress/"; //I am providing an ip adress
driver.manage().timeouts().implicitlyWait(30, TimeUnit.SECONDS);
}
@Test
public void testTryZencart() throws Exception {
driver.get(baseUrl + "/zencart/index.php?main_page=index&cPath=1_16");
try{
int x = 3;
int y = 0;
driver.navigate().refresh();
while(x<10){
y=y+1;
System.out.println("We have now started the " + y + " iteration, which means that whenever we stop the execution the {$y} iteration was going on.");
driver.findElement(By.xpath("//td/div/div/div/a")).click();
driver.findElement(By.xpath("//td/div/div[2]/div/a")).click();
driver.findElement(By.xpath("//div[2]/div/a[2]")).click();
driver.findElement(By.xpath("//div[2]/div/a[3]")).click();
driver.findElement(By.xpath("//div[12]/div/a[4]")).click();
driver.findElement(By.xpath("//a[5]")).click();
driver.findElement(By.xpath("//a[6]")).click();
driver.findElement(By.xpath("//a[7]")).click();
driver.findElement(By.xpath("//a[8]")).click();
driver.findElement(By.xpath("//a[9]")).click();
driver.navigate().refresh();
}
}
catch(NoSuchElementException e)
{
System.out.println("\nArjun no good!!");
driver.navigate().refresh();
}
}
@After
public void tearDown() throws Exception {
driver.quit();
String verificationErrorString = verificationErrors.toString();
if (!"".equals(verificationErrorString)) {
fail(verificationErrorString);
}
}
private boolean isElementPresent(By by) {
try {
driver.findElement(by);
return true;
} catch (NoSuchElementException e) {
return false;
}
}
private boolean isAlertPresent() {
try {
driver.switchTo().alert();
return true;
} catch (NoAlertPresentException e) {
return false;
}
}
private String closeAlertAndGetItsText() {
try {
Alert alert = driver.switchTo().alert();
String alertText = alert.getText();
if (acceptNextAlert) {
alert.accept();
} else {
alert.dismiss();
}
return alertText;
} finally {
acceptNextAlert = true;
}
}
}
所以现在我希望执行在触发异常后返回try块。反正有没有这样做。
答案 0 :(得分:4)
你可以在while循环
中完成boolean isSuccessful = false;
while(!isSuccessful){
try{
// do whatever you want
isSuccessful = true;
}catch(Exception e){
// Exception so lets do it again
}
}
答案 1 :(得分:2)
将try/catch
阻止置于内while
循环:
while (x < 10)
{
try
{
...
}
catch (NoSuchElementException e)
{
...
}
}
顺便说一下,你还应该在循环内增加x
...
答案 2 :(得分:1)
使用xpath作为参数创建一个新方法,并使用try-catch
块来调用driver.findElement
。
使用此方法代替直接调用driver.findElement
。
答案 3 :(得分:0)
您可以引入一些逻辑来重新执行try-catch
作为示例一个方法 - do-while
循环,其中检查循环条件,尝试是否已执行!
boolean reLoop = false;
do{
try{
// your code
}catch(Exception ex){
// handle your exception
reLoop = true;
}
}while(tryExecuted);
要考虑的一个重要事项是infinite-loop
,如果您的尝试每次都失败,在这种特定情况下,请考虑应执行try
块的最大数量。
boolean reLoop = false;
int loopMaxCount = 3; // assumed maximum number of re looping
int loopCont = 0;
do{
loopCont++;
try{
// your code
}catch(Exception ex){
// handle your exception
if(loopCont < loopMaxCount) // It blocks infinite looping
reLoop = true;
}
}while(tryExecuted);
答案 4 :(得分:0)
无法从catch
返回try
阻止。
您必须重新设计代码 - 将每个findElement()
方法包装在单独的try/catch
块中,或者使用其他答案中建议的循环。 (我想在你的代码中会有太多的循环 - 第二个将迭代你的所有xpath参数,如:"//td/div/div/div/a"
等。)。