Question

如果你在WP_QUERY中传递这些args时看到下面的代码，那么它将生成一个查询，它会将％包裹在测试中像这样的东西

 " AND CAST(wp_postmeta.meta_value AS CHAR) LIKE '%test%') ) "

有没有可能我想在'test'字符串的开头只有％？

$args = array(
    'post_type' => 'job_listing',
    'post_status' => 'publish',
    'orderby' => 'date',
    'order' => 'DESC',
    'meta_query' => array(
         array(
          'key' => 'geo_address',
          'value' => 'test',
          'compare' => 'LIKE'
      )
    )

);

Answer 1

你不能这样做，因为wp_query自动添加％..％。但是，您可以使用自定义查询执行此操作，例如;

global $wpdb;

$specific_posts = $wpdb->get_results("SELECT * FROM `wp_posts` WHERE 
post_type='job_listing' AND post_status ='publish' AND ID
 IN(
SELECT post_id FROM `wp_postmeta` WHERE meta_key='geo_address' 
AND meta_value LIKE '%test'
) ORDER BY post_date DESC");

修改：如果您不想使用自定义查询执行此操作，则需要使用wp之类的posts_where操作;

add_filter( 'posts_where', 'custom_posts_where', 10, 2 );
function custom_posts_where( $where, &$wp_query )
{
    global $wpdb;
    if ( $custom_post_meta_value = $wp_query->get( 'custom_value' ) ) {
        $where .= ' AND ' . $wpdb->postmeta . '.meta_key = "geo_address" AND ' . $wpdb->postmeta . '.meta_value LIKE \'' . esc_sql( like_escape( $custom_post_meta_value ) ) . '\'';
    }
    return $where;
}

在您的查询中，使用如下所示;

$args = array(
    'post_type' => 'job_listing',
    'post_status' => 'publish',
    'orderby' => 'date',
    'order' => 'DESC',
    'meta_query' => array(
         array(
          'key' => 'geo_address',
          'custom_value' => '%test',
          'compare' => 'LIKE'
      )
    )

);

Answer 2

这是另一个解决方案，我想我会尝试两个

function filter_meta_query( $pieces ) {

    if ( !empty( $pieces['where'] ) ) {
        $pieces['where'] = preg_replace( '/(.*?)LIKE \'\%(.*?)\%\'/', "\$1LIKE '\$2%'", $pieces['where'] );
    }

    return $pieces;
}


add_filter( 'get_meta_sql', 'filter_meta_query' );

$args = array(
    'meta_query' => array(
        array(
            'key' => 'any_key',
            'compare' => 'LIKE',
            'value' => '%test'
        )
    )
);

// the query
$query = new WP_Query( $args );

// remove it after the query.
remove_filter( 'get_meta_sql', 'filter_meta_query' );

Answer 3

似乎这篇文章解决了使用REGEX而不是LIKE的问题： https://wordpress.stackexchange.com/questions/159426/meta-query-with-string-starting-like-pattern

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