Question

const int CHECK_MAX = 50;

void balanceAccount(double account)
{
    double start = 0;
    double interest = 0;
    double check[CHECK_MAX];

    account = (start - check[CHECK_MAX]) * (1 + interest);
    cout << account;
}

int main()
{
    int sub;
    double start = 0;
    double interest = 0;
    double total = 0;
    double check[CHECK_MAX];
    void balanceAccount(double);

    cin >> start;

   for (sub = 0; sub < CHECK_MAX; sub++)
    {
        cin >> check[sub];

        if (check[sub] == 0)
        {
            cout << "Thank you." << endl;
            break;
        }
    }

   cin >> interest;

    if (interest == 0)
    {
        balanceAccount(total);
    }
        else
    {
            balanceAccount(total);
    }

    return 0;
}

此程序的目的是提示用户输入银行帐户的起始余额，然后使用数组，输入单独的支票金额（最多50个），并从初始余额中减去它们。然后，如果存在利息值，则将其乘以总数。结束结果使用balanceAccount（）函数计算。我相信一切正常，直到最后的计算。我一直得到不正确的计算。我最终将包含一种货币格式，但现在我只是想让它正确计算。谢谢你的时间。

Answer 1

double check[CHECK_MAX];

account = (start - check[CHECK_MAX]) * (1 + interest);

访问check[CHECK_MAX]无效 - 它正在运行数组的末尾。 C ++数组的索引为0-n-1，因此数组中的最后一项是check[CHECK_MAX-1]。

Answer 2

balanceAccount()中的所有变量都被初始化为零，因此main()中的其他变量无效。要解决此问题，请将变量传递给balanceAccount()：

void balanceAccount(double localAccount, double localStart, double localInterest, double localCheck[])
{
    account = (start - check[CHECK_MAX]) * (1 + interest);
    cout << account;
}

您可能还想返回account。＆＃39;

这一行：

account = (start - check[CHECK_MAX]) * (1 + interest);

超过数组的末尾，它应该是：

account = (start - check[CHECK_MAX-1]) * (1 + interest);

我也不知道你在if...else结束时对main()所做的事情。

Answer 3

将balanceAccount（）方法改为如下..

double balanceAccount(char account[])
{
    double start = 0;
    double interest = 0;
    double check[CHECK_MAX];

    double account = (start - check[CHECK_MAX-1]) * (1 + interest);
    cout << account;
}

主要balanceAccount()

total = balanceAccount(check);

在check中传递balanceAccount()的原因;您在check和main()中创建了不同的balanceAccount()，两者都不相同...... < / p>

同样check[CHECK_MAX]操作无效... 0 to CHECK_MAX-1是有效的内存位置，根据上面的代码更改为CHECK_MAX ...更改

Answer 4

基于您的陈述的工作代码试试这个，

  #include<iostream>
using namespace std;

const int CHECK_MAX = 50;

void balanceAccount(double total,double interest)
{
    double account = (total) * (interest);
    cout << account;
}

int main()
{
    int sub;
    double start = 0;
    double interest = 0;
    double total = 0;
    double check[CHECK_MAX];
    void balanceAccount(double,double);

    cout << "Enter the beginning balance of the account at the beginning of the month." << endl;
    cin >> start;
    total = start;
    cout << "Enter the individual dollar amount of checks written this month." << endl;
    cout << "A maximum number of 50 checks is enforced." << endl;
    cout << "Enter a zero when you are finished entering check values." << endl;
    for (sub = 0; sub < CHECK_MAX; sub++)
    {
        cout << "Enter the dollar amount for the checks written, but one at a time." << endl;
            cin >> check[sub];
        total = total - check[sub];
        if (check[sub] == 0)
        {
            cout << "Thank you." << endl;
            break;
        }
    }

    cout << "If applicable, enter an interest rate." << endl;
    cout << "If there is no interest rate, enter a 0." << endl;
    cin >> interest;
    if(interest != 0)
    {
        cout << "Thank you." << endl;
        balanceAccount(total,interest);
    }
    else
    {
        cout << "Thank you." << endl;
        cout << total << endl;
    }
    return 0;
}

功能未返回正确的结果

4 个答案: