Question

似乎无法想出这一个。我想将三个不同表中的数据放入我页面中的一个表中。

我的桌子

People
+----+------+--------+------+
| id | name | status | date |
+----+------+--------+------+

House
+----+---------+--------+------+
| id | address | status | date |
+----+---------+--------+------+

Alarms
+----+------+--------+------+
| id | type | status | date |
+----+------+--------+------+

我想从状态为2的那三个表中获取所有数据。我怎么能这样做并将它们放在按日期排序的一个html表中。

如果有人能指出正确的方向，那就太棒了。

Answer 1

试试这个

 SELECT p.id,
        p.name,
        p.status,
        p.date, 
        h.address,
        a.type
 FROM people p
 INNER JOIN House h ON p.id = h.id  //this i just guessed the relation you should make your relation here
 INNER JOIN Alarms a ON h.id = a.id //this i just guessed the relation you should make your relation here
 WHERE p.status =2
 ORDER BY p.date

如果你的表没有关系，那就试试这个

 select id,'type' as type,name,'adress' as adress,status,date  from people where status =2
 union
 select id,'type' as type,name,adress,status,date  from House where status =2
 union
 select id,type,name,'adress' as adress,status,date  from people where status =2

来自多个不同MySQL表的HTML表，具有不同的数据

1 个答案: