Question

我希望使用mongoDB的聚合框架获取特定查询。我想我需要$ group和$ addToSet运算符，但我对使用正确的查询感到困惑。

这是文章集：

/* 0 */
{
    "_id" : 4,
    "author" : "Kevin Vanhove",
    "book" : {
        "order" : 500,
        "title" : "HTML",
        "url" : "html"
    },
    "chapter" : {
        "img" : "navChapter-logo",
        "order" : 500,
        "title" : "W3C",
        "url" : "w3c"
    },
    "featured" : 0,
    "heading" : [ 
        {
            "title" : "title1",
            "_id" : ObjectId("53130fb8b9b9f573a877401d")
        }, 
        {
            "title" : "title2",
            "_id" : ObjectId("53130fb8b9b9f573a877401c")
        }
    ],
    "intro" : "Some intro text",
    "title" : "Internet with and without the W3C",
    "url" : "internet-with-and-without-the-W3C"
}

/* 1 */
{
    "_id" : 1,
    "author" : "Kevin Vanhove",
    "book" : {
        "order" : 500,
        "title" : "Javascript",
        "url" : "javascript"
    },
    "chapter" : {
        "img" : "navChapter-logo",
        "order" : 500,
        "title" : "Functions",
        "url" : "functions"
    },
    "featured" : 1,
    "heading" : [ 
        {
            "title" : "Parts of a function",
            "_id" : ObjectId("53130e0cd8517b65a614c1ab")
        }, 
        {
            "title" : "Something else",
            "_id" : ObjectId("53130e0cd8517b65a614c1aa")
        }
    ],
    "intro" : "Some intro text",
    "title" : "A visual illustration of the JS function",
    "url" : "a-visual-illustration-of-the-javascript-function"
}

/* 2 */
{
    "_id" : 2,
    "author" : "Kevin Vanhove",
    "book" : {
        "order" : 500,
        "title" : "Javascript",
        "url" : "javascript"
    },
    "chapter" : {
        "img" : "navChapter-logo",
        "order" : 300,
        "title" : "Variables",
        "url" : "variables"
    },
    "featured" : 1,
    "heading" : [ 
        {
            "title" : "Global vs local",
            "_id" : ObjectId("53130ea8a9dc9c28a77ea28a")
        }, 
        {
            "title" : "Variable hoisting",
            "_id" : ObjectId("53130ea8a9dc9c28a77ea289")
        }, 
        {
            "title" : "The scope chain",
            "_id" : ObjectId("53130ea8a9dc9c28a77ea288")
        }
    ],
    "intro" : "Some intro text",
    "title" : "How variable scope works in javascript",
    "url" : "how-variable-scope-works-in-javascript"
}

/* 3 */
{
    "__v" : 0,
    "_id" : 3,
    "author" : "Kevin Vanhove",
    "book" : {
        "order" : 500,
        "title" : "Javascript",
        "url" : "javascript"
    },
    "chapter" : {
        "img" : "navChapter-logo",
        "order" : 600,
        "title" : "Functions",
        "url" : "functions"
    },
    "featured" : 0,
    "heading" : [ 
        {
            "title" : "title1",
            "_id" : ObjectId("53130f60f0de2506a81e2d62")
        }, 
        {
            "title" : "title2",
            "_id" : ObjectId("53130f60f0de2506a81e2d61")
        }
    ],
    "intro" : "Some intro text",
    "title" : "Javascript closures, in depth",
    "url" : "Javascript-closure-in-depth"
}

我需要拥有所有“独特”的书籍及其“独特”章节（不重复），所以我使用此查询：

/*
db.articles.aggregate({$group : {_id : "$book.title", chapters:{$addToSet:"$chapter.title"}}})
*/

这给了我这个结果：

/* 0 */
{
    "result" : [ 
        {
            "_id" : "Javascript",
            "chapters" : [ 
                "Variables", 
                "Functions"
            ]
        }, 
        {
            "_id" : "HTML",
            "chapters" : [ 
                "W3C"
            ]
        }
    ],
    "ok" : 1
}

这几乎是我想要但不完全的。实际需要的是：

/* 0 */
{
    "result" : [ 
        {
            "_id" : "Javascript",
            "chapters" : [ 
                {
                    "img" : "navChapter-logo",
                    "order" : 600,
                    "title" : "Functions",
                    "url" : "functions"
                }, 
                {
                    "img" : "navChapter-logo",
                    "order" : 300,
                    "title" : "Variables",
                    "url" : "variables"
                }
            ]
        }, 
        {
            "_id" : "HTML",
            "chapters" : [ 
                {
                    "img" : "navChapter-logo",
                    "order" : 500,
                    "title" : "W3C",
                    "url" : "w3c"
                }
            ]
        }
    ],
    "ok" : 1
}

所以我需要所有独特的书籍及其独特的章节，但我也希望添加额外的字段，如“订单”和“网址”。我现在使用的查询只给了章节标题。

更新

我也试过：$ addToSet：“$ chapter”而不是$ addToSet：“$ chapter.title”......

但是现在我在chapter.title字段上得到重复。我在书'javascript'中只能得到2个不同的章节，现在我得到3章（1个重复）

Answer 1

您可以使用$group按书籍和章节汇总。

db.articles.aggregate（

{$group : {_id : {t:"$book.title",c:"$chapter.title"}, 
           img:{$first:"$chapter.img"},
           url:{$first:"$chapter.url"},
           order:{$sum:"$chapter.order"}
}})

如果顺序很重要，我保留了它并将它们添加到同一本书的“重复”章节中。

MongoDB聚合框架：组查询

1 个答案: