在UISearchBar中按“x”时关闭键盘

Question

如果我将resign代码放在​​我的if条件下键盘不会退出，如果我评论if条件我的键盘辞职。

- (void)searchBar:(UISearchBar *)searchBar textDidChange:(NSString *)searchText
{
    if (searchText.length == 0) {
        [searchBar resignFirstResponder];
    }
}

我想在用户按下“x”按钮时退出键盘，即UISearchBar文本为空时。有没有办法做到这一点？

Answer 1

只是辞职第一个响应者，但是在下一个运行循环中这样：

- (void)searchBar:(UISearchBar *)searchBar textDidChange:(NSString *)searchText 
{
    if ([searchText length] == 0) 
    {
        [searchBar performSelector:@selector(resignFirstResponder)
                   withObject:nil 
                   afterDelay:0];
    }
}

经过测试，确实有效。

Answer 2

针对switf 3进行了更新：

func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {
    if searchBar.text == nil || searchBar.text == ""
    {
       searchBar.perform(#selector(self.resignFirstResponder), with: nil, afterDelay: 0.1)
    }
}

Answer 3

添加“取消按钮”以查看加载和添加方法-> searchBarCancelButtonClicked

searchBar.showsCancelButton = true

func searchBarCancelButtonClicked(_ searchBar: UISearchBar) {
  searchBar.resignFirstResponder()
}

Answer 4

- (void)searchBar:(UISearchBar *)searchBar textDidChange:(NSString *)searchText {
NSRange foundRange = [searchText rangeOfString:@"x"];
if (foundRange.location != NSNotFound) {
    if (searchText.length == 0) {
        [searchBar resignFirstResponder];
        }
    }
}