Question

我正在尝试与DX类接口并出现构造错误。

public interface IDevice
{

}

class vJoystick : Joystick, IDevice
{   //ERROR Joystick does not take 0 parms...
    public vJoystick( Joystick joystick) {}
}

class vMouse : Mouse, IDevice
{   //ERROR Mouse does not take 0 parms...
    public vMouse( Mouse mouse ) { }
}

public class DeviceFactory
{
    public static IDevice Create( object device, DirectInput di, Guid g )
    {
        if ( device is Joystick ) return new vJoystick( new Joystick(di, g) );
        if ( device is Mouse )    return new vMouse( new Mouse ( di ));
        return new vJoystick( new Joystick( di, g ) );//defult
    }
}

见上面的评论。如何让我的类传递我的类构造的参数？

这也是一个很好的用法，看起来像是过度杀人？

Joystick device = ( Joystick ) DeviceFactory.Create( ( Joystick ) new Object(), directInput, deviceGuid );

更新：根据以下建议添加此内容。

  class vJoystick :  IDevice, Joystick
        {
            private  Joystick joystick;
            public vJoystick( DirectInput di, Guid g )
            {
                joystick = new Joystick(di,g);
            }
        }

        class vMouse : IDevice, Mouse
        {
            private  Mouse mouse;
            public vMouse( DirectInput di)
            {
                mouse = new Mouse( di);
            }
        }

Answer 1

如果你真的需要继承（我不太相信是这种情况），试试这个：

public interface IDevice
{

}

class vJoystick : Joystick, IDevice
{
    public vJoystick(DirectInput di, Guid g) : base(di, g) {}
}

class vMouse : Mouse, IDevice
{
    public vMouse( DirectInput di ) : base(di) { }
}

public class DeviceFactory
{
    public static IDevice Create( object device, DirectInput di, Guid g )
    {
        if ( device is Joystick ) return new vJoystick(di, g);
        if ( device is Mouse )    return new vMouse(di);
        return new vJoystick(di, g);//defult
    }
}

基本上，由于您从vJoystick派生Joystick，base(di, g)实际上与new vJoystick(di, g)做同样的事情。您无法从C＃中的基类型创建派生类型的实例（即扩展它）。

另外，如果你想使用.NET中的DX，我建议使用一个适用于.NET的托管包装器，例如SlimDX或SharpDX。你会节省很多时间，除非你非常了解你正在做什么，否则它也会显着改善你的表现。更不用说减少内存泄漏的发生率和其他有趣的东西:)

c＃接口和第三方类构造的麻烦

1 个答案: