Question

我在数据库中有如下数据：

+---------------------+-------------+
|        CloseTime    |       Count |
+---------------------+-------------+
|     10.2.2014 13:19 |   1         |
|     5.12.2014 13:19 |   1         |
|     4.2.2014 13:19  |   1         |
|     2.1.2014 13:19  |   1         |
|     4.12.2014 13:19 |   1         |
+---------------------+-------------+

现在，我有这样的查询

SELECT DATENAME(MONTH, CLOSETIME) AS CLOSEMONTH, COUNT(*) as CNT
FROM TABLE
WHERE CLOSETIME >= DATEADD(MONTH, DATEDIFF(MONTH, '19000101', GETDATE())-7, '19000101')
AND CLOSETIME <  DATEADD(MONTH, DATEDIFF(MONTH, '19000101', GETDATE()), '19000101')
GROUP BY DATENAME(MONTH, CLOSETIME);

导致

+---------------+-------+
|     CloseTime |  CNT  |
+---------------+-------+
|     February  | 2     |
|     January   | 1     |
|     December  | 2     |
+---------------+-------+

查询的工作方式是过去7个月的数据。我需要结果

+---------------+-------+
|     CloseTime | Count |
+---------------+-------+
|     February  | 2     |
|     January   | 1     |
|     December  | 2     |
|     November  | 0     |
|     October   | 0     |
|     September | 0     |
|     August    | 0     |
+---------------+-------+

因此，如果在以后的几个月内没有关闭时间的记录，它仍应返回零计数的月份。怎么做到这一点？我更喜欢SQL解决方案，这意味着没有程序或脚本。

我试过

SELECT DATENAME(MONTH,DATEADD(MONTH,-1,GETDATE())) as HELP_MONTH
UNION ALL
...

然后加入它，但它没有成功。

Answer 1

通过添加HAVING子句使用相同的查询将添加具有0计数的记录。

SELECT DATENAME(MONTH, CLOSETIME) AS CLOSEMONTH, COUNT(*) as CNT
FROM TABLE
WHERE CLOSETIME >= DATEADD(MONTH, DATEDIFF(MONTH, '19000101', GETDATE())-7, '19000101')
AND CLOSETIME <  DATEADD(MONTH, DATEDIFF(MONTH, '19000101', GETDATE()), '19000101')
GROUP BY DATENAME(MONTH, CLOSETIME)
HAVING COUNT(*) >= 0

感谢。

Answer 2

以下查询可以使用您的结果集进行LEFT JOIN：

SELECT * FROM
(
   SELECT 'January' AS month_name, 1 AS month_num
   UNION
   SELECT 'February',2
   UNION 
   SELECT 'Mar',3
   UNION 
   SELECT 'Apr',4
   UNION 
   SELECT 'May',5
   UNION 
   SELECT 'June',6
   UNION 
   SELECT 'July',7
   UNION
   SELECT 'August', 8
   UNION
   SELECT 'September', 9
   UNION
   SELECT 'October', 10
   UNION
   SELECT 'November', 11
   UNION
   SELECT 'December', 12
)
months
WHERE month_num <= MONTH(GETDATE())
OR month_num  > (MONTH(GETDATE()) - 7) % 12 + 12

以上查询给出了结果集的最后7个月：

以下是SQL Fiddle

的代码

Answer 3

好的，这对我有用：

WITH HM (HELP_MONTH) AS (
SELECT DATENAME(MONTH,DATEADD(MONTH,-1,GETDATE())) AS HELP_MONTH
UNION ALL
SELECT DATENAME(MONTH,DATEADD(MONTH,-2,GETDATE())) AS HELP_MONTH
UNION ALL
SELECT DATENAME(MONTH,DATEADD(MONTH,-3,GETDATE())) AS HELP_MONTH
UNION ALL
SELECT DATENAME(MONTH,DATEADD(MONTH,-4,GETDATE())) AS HELP_MONTH
UNION ALL
SELECT DATENAME(MONTH,DATEADD(MONTH,-5,GETDATE())) AS HELP_MONTH
UNION ALL
SELECT DATENAME(MONTH,DATEADD(MONTH,-6,GETDATE())) AS HELP_MONTH
UNION ALL
SELECT DATENAME(MONTH,DATEADD(MONTH,-7,GETDATE())) AS HELP_MONTH)
SELECT HELP_MONTH
,COUNT(CNT) AS CNT
FROM HM
LEFT JOIN YOUR_TABLE ON HM.HELP_MONTH = DATENAME(MONTH, CLOSETIME)
AND CLOSETIME >= DATEADD(MONTH, DATEDIFF(MONTH, '19000101', GETDATE())-7, '19000101')
AND CLOSETIME <  DATEADD(MONTH, DATEDIFF(MONTH, '19000101', GETDATE()), '19000101')
GROUP BY DATENAME(MONTH, CLOSETIME), HELP_MONTH

数数月没有记录

3 个答案: