Question

我想从给定的字符串，使用php和正则表达式以@xxx开头的单词中列出特定的单词。

e.g：

沃尔沃卡车 - Rajnikanth - 史诗般的分裂壮举。（现场测试6）@xyz Thalaivar Epic Split Rajanikanth Rajinikanth Rajani Auto Auto rikshaw以及@ xyz.abc http://another.net @ bac.def这是测试@pqr

我希望返回值像@xyz，@ xyz.abc，@ bac.def，@ pqr这句话来自上面的字符串。

我不知道正则表达。

Answer 1

这样做

<?php
$input_lines="Volvo Trucks - Rajnikanth - The Epic Split feat. (Live Test 6) @xyz Thalaivar Epic Split Rajanikanth Rajinikanth Rajani Auto Auto rikshaw and also @xyz.abc http://another.net @bac.def this is tesging @pqr";
preg_match_all("/(@\w+[^\s+]+)/", $input_lines, $output_array);
print_r($output_array[1]);

Demo

<强>输出：

Array
(
    [0] => @xyz
    [1] => @xyz.abc
    [2] => @bac.def
    [3] => @pqr
)

Answer 2

替代解决方案......虽然不是正则表达式..

<?php
$str='Volvo Trucks - Rajnikanth - The Epic Split feat. (Live Test 6) @xyz Thalaivar Epic Split Rajanikanth Rajinikanth Rajani Auto Auto rikshaw and also @xyz.abc http://another.net @bac.def this is tesging @pqr';
$newarr[]=array_map(function ($v){ return $v='@'.explode(' ',$v)[0];},explode('@',$str));unset($newarr[0][0]);
print_r($newarr);

<强> OUTPUT :

Array
(
    [0] => @xyz
    [1] => @xyz.abc
    [2] => @bac.def
    [3] => @pqr
)

想从给定字符串中获取列表的特定单词

2 个答案: