Question

我是Xamarin IOS的新手，我有一个需要这个弹出式导航的项目。

var navigation = new FlyoutNavigationController {
                    // Create the navigation menu
                    NavigationRoot = new RootElement ("Navigation") {
                        new Section ("Menu") {
                            new StringElement ("Recipe"),
                            new StringElement ("Recipe Basket"),
                            new StringElement ("Meal Planner"),
                            new StringElement ("Grocery List"),
                            new StringElement ("Social"),
                            new StringElement ("Videos"),
                            new StringElement ("News Feed"),
                            new StringElement ("Partners"),
                        }
                    },
                    // Supply view controllers corresponding to menu items:

                    ViewControllers = new [] {
                        new UIViewController { View = new UILabel { Text = "Animals (drag right)" } },
                        new UIViewController { View = new UILabel { Text = "Vegetables (drag right)" } },
                        new UIViewController { View = new UILabel { Text = "Minerals (drag right)" } },


                    },
                };

此代码仅显示UILabel。如何将其发送到特定的视图控制器？

请帮忙。

提前致谢。

Answer 1

做vinaykumar所说的，但你也想从那些UIViewControllers中打开FlyoutNavigationController，所以你必须将你创建的那个初始传递给那些控制器。

否则，如果您只是打开视图控制器，则无法再次获取菜单。

我打开导航控制器是这样的：

ViewDidLoad中的MainViewController：

        UIStoryboard board = UIStoryboard.FromName("MainStoryboard_iPhone", null);

        UINavigationController nav = (UINavigationController)board.InstantiateViewController("nav");
        SearchViewController searchVC = (SearchViewController)nav.ViewControllers[0];

         // Passing flyoutnavigation here
        searchVC.navigation = navigation;

        SettingsViewController settingsVC = (SettingsViewController)board.InstantiateViewController("settings");
        UINavigationController navSettings = new UINavigationController(settingsVC);

        // Passing flyoutnavigation here
        settingsVC.navigation = navigation;

        navigation.ViewControllers = new[]
        {
            nav,
            navSettings
        };

在其他视图控制器（我的例子中的设置和搜索）中，我有一个公共变量来存储FlyoutNavigationController（在MainViewController中设置），然后添加一个按钮来打开传递的FlyoutNavigationController：

    // Set in MainViewController
    public FlyoutNavigationController navigation;

    public override void ViewDidLoad()
    {

        base.ViewDidLoad();

        // Add button to allow opening the FlyoutNavigationController
        NavigationItem.LeftBarButtonItem = new UIBarButtonItem(UIBarButtonSystemItem.Action, delegate
        {
            navigation.ToggleMenu();
        });
    }

Answer 2

您必须将FlyoutNavigationController's View添加到View

// Show the navigation view
navigation.ToggleMenu ();
View.AddSubview (navigation.View);

Answer 3

此代码仅显示UILabel。

因为您只提供UILable作为新UIViewController的视图。

View = new UILabel { Text = "Animals (drag right)" }

如何将其发送到特定的视图控制器？

提供您的UIViewController而不是新的UIViewController

例如，

更改以下代码

ViewControllers = new [] {
                        new UIViewController { View = new UILabel { Text = "Animals (drag right)" } },
                        new UIViewController { View = new UILabel { Text = "Vegetables (drag right)" } },
                        new UIViewController { View = new UILabel { Text = "Minerals (drag right)" } },

                },

到

ViewControllers = new [] {
                            new <your_UIViewController>(),
                            new <your_UIViewController>(),
                            new <your_UIViewController>(),

                    },

希望这对您有所帮助，如果您在实施同样的问题时遇到任何问题，请告诉我。

如何在xamarin IOS中使用弹出导航

3 个答案: