Question

我有这个查询来快速搜索我的数据库

$result = $apt->query("SELECT * FROM news where title like '%$searchfor%' order by item_id DESC limit 20");

我想在此搜索查询中包含“post”行的前100个字符以及标题行。有时我会在“post”行的前100个字符中找到人们可能搜索的一些字符。

任何想法？谢谢

Answer 1

您可以选择整个post和title并在PHP中截断它

<强> SQL

SELECT post, title 
FROM news WHERE title LIKE '%$searchfor%' 
ORDER BY item_id DESC 
LIMIT 20

<强> PHP

function limit_words($words, $limit, $append = ' &hellip;') {
    $limit = $limit+1;
    $words = explode(' ', $words, $limit);
    array_pop($words);
    $words = implode(' ', $words) . $append;

    return $words;
}

// this actually will give you 100 words
echo limit_words($result->post, 100);

// this will give you 100 characters
echo substr($result->post, 0, 100);

还有一种方法可以在SQL中直接执行，可以节省一些内存。

<强> SQL

SELECT SUBSTRING(post, 0, 100) AS post, title
FROM news WHERE title LIKE '%$searchfor%' 
ORDER BY item_id DESC 
LIMIT 20

如果要同时搜索title和post字段，则需要将它们添加到WHERE子句中：

<强> SQL

SELECT post, title 
FROM news 
WHERE title LIKE '%searchfor%' AND post LIKE '%searchfor%'
ORDER BY item_id DESC 
LIMIT 20

### If you need to map search term in either post OR title ###

SELECT post, title 
FROM news 
WHERE title LIKE '%searchfor%' OR post LIKE '%searchfor%'
ORDER BY item_id DESC 
LIMIT 20

PHP，Mysql搜索查询前100个字符

1 个答案: