如何通过符文数组拆分GO中的字符串？

Question

如果有任何方法将字符串拆分为字符串数组，那么当你将符号作为符号数组时？有一个我想要的例子：

seperators = {' ',')','('}
SomeFunction("my string(qq bb)zz",seperators) => {"my","string","qq","bb","zz"}

Answer 1

例如，

package main

import (
    "fmt"
    "strings"
)

func split(s string, separators []rune) []string {
    f := func(r rune) bool {
        for _, s := range separators {
            if r == s {
                return true
            }
        }
        return false
    }
    return strings.FieldsFunc(s, f)

}

func main() {
    separators := []rune{' ', ')', '('}
    s := "my string(qq bb)zz"
    ss := split(s, separators)
    fmt.Printf("%q\n", s)
    fmt.Printf("%q\n", ss)
}

输出：

"my string(qq bb)zz"
["my" "string" "qq" "bb" "zz"]

Answer 2

使用正则表达式：

package main

import (
    "fmt"
    "regexp"
)

var re = regexp.MustCompile("[() ]")

func main() {
    text := "my string(qq bb)zz"
    splinedText := re.Split(text, -1)
    fmt.Printf("%q\n", text)
    fmt.Printf("%q\n", splinedText)
}

输出：

"my string(qq bb)zz"
["my" "string" "qq" "bb" "zz"]