Question

我在libchart中使用PHP，但我对如何统计数据库中的男性和女性有疑问。我正在使用wampserver：

<?php
    include "../libchart/libchart/classes/libchart.php";

    define('DB_HOST', 'localhost');
    define('DB_NAME', 'login');
    define('DB_USER','root');
    define('DB_PASSWORD','');

    $con=mysql_connect(DB_HOST,DB_USER,DB_PASSWORD) or die("Failed to connect to                                        MySQL: " . mysql_error());
    $db=mysql_select_db(DB_NAME,$con) or die("Failed to connect to MySQL: " . mysql_error());

    header("Content-type: image/png");

    $chart = new PieChart(500, 300);
    $query1= "Select count(*) from users where gender='Male'";
    $query2= "Select count(*) from users where gender='Female'";
    $male=$query1;
    $female=$query2;
    $dataSet = new XYDataSet();
    $dataSet->addPoint(new Point("Male", $male));
    $dataSet->addPoint(new Point("Female", $female));
    $chart->setDataSet($dataSet);

    $chart->setTitle("Number of Female and Male");
    $chart->render();


?>

Answer 1

您永远不会费心执行查询 - 您所做的就是定义一些在其中包含SQL的字符串。另外，不需要两个单独的查询：

$sql = "SELECT gender, count(*) AS cnt FROM users WHERE gender IN ('Male', 'Female') GROUP BY gender");
$result = mysql_query($sql) or die(mysql_error());
while($row = mysql_fetch_assoc($result)) {
    $dataSet->addPoint(new Point($row['gender'], $row['cnt']));
}

Answer 2

<?php
    include "../libchart/libchart/classes/libchart.php";

    define('DB_HOST', 'localhost');
    define('DB_NAME', 'login');
    define('DB_USER','root');
    define('DB_PASSWORD','');

    $con=mysql_connect(DB_HOST,DB_USER,DB_PASSWORD) or die("Failed to connect to                                        MySQL: " . mysql_error());
    $db=mysql_select_db(DB_NAME,$con) or die("Failed to connect to MySQL: " . mysql_error());

    header("Content-type: image/png");

    $chart = new PieChart(500, 300);
    $query = "Select (Select count(*) from users where gender='Male') AS Male, (Select count(*) from users where gender='Female') as Female";
    $data = mysql_query($query);
    $male=$data[0]['Male'];
    $female=$data[0]['Male'];
    $dataSet = new XYDataSet();
    $dataSet->addPoint(new Point("Male", $male));
    $dataSet->addPoint(new Point("Female", $female));
    $chart->setDataSet($dataSet);

    $chart->setTitle("Number of Female and Male");
    $chart->render();


?>

PHP计数数据库中的男性和女性到CHART

2 个答案: