在这段代码中,我尝试在不存在的表上运行select,getJobReference()
返回NULL
,我很想抓住这种错误,并希望收到错误消息以某种方式获得。
如果出现故障时如何获取错误消息?
$client = new Google_Client();
$client->setApplicationName("Client_Library_Examples");
//$client->setDeveloperKey(API_KEY);
if (isset($_SESSION['service_token'])) {
$client->setAccessToken($_SESSION['service_token']);
}
$key = file_get_contents($key_file_location);
$cred = new Google_Auth_AssertionCredentials(
$service_account_name, array(
'https://www.googleapis.com/auth/bigquery',
), $key
);
$client->setAssertionCredentials($cred);
if ($client->getAuth()->isAccessTokenExpired()) {
$client->getAuth()->refreshTokenWithAssertion($cred);
}
$_SESSION['service_token'] = $client->getAccessToken();
var_dump($_SESSION);
$bq = new Google_Service_Bigquery($client);
//build query
$sql = 'select * from example.table LIMIT 10';
$job = new Google_Service_Bigquery_Job();
$config = new Google_Service_Bigquery_JobConfiguration();
$queryConfig = new Google_Service_Bigquery_JobConfigurationQuery();
$config->setQuery($queryConfig);
$job->setConfiguration($config);
$queryConfig->setQuery($sql);
$insert = new Google_Service_Bigquery_Job($bq->jobs->insert(PROJECT_ID, $job));
$jr = $insert->getJobReference();
var_dump($jr);/*THIS RETURNS NULL */
$jobId = $jr['jobId'];
$res = new Google_Service_Bigquery_GetQueryResultsResponse($bq->jobs->getQueryResults(PROJECT_ID, $jobId));
//see the results made it as an object ok:
var_dump($res);
答案 0 :(得分:4)
他们的API会自动创建一些类,并在创建时使用错误。
我在调试过程结束后得到了这样的错误:
try {
$job = $bq->jobs->insert(PROJECT_ID, $job);
$status = new Google_Service_Bigquery_JobStatus();
$status = $job->getStatus();
// print_r($status);
if ($status->count() != 0) {
$err_res = $status->getErrorResult();
die($err_res->getMessage());
}
} catch (Google_Service_Exception $e) {
echo $e->getMessage();
exit;
}
一般方法是查看您正在使用的服务是否有Status
类。只有在抛出错误时,才会激活异常块,即dryRun
处于活动状态时。
$config->setDryRun(true);
答案 1 :(得分:1)
我不太了解这个SDK,但你检查过你是否得到例外吗?
try {
$insert = new Google_Service_Bigquery_Job($bq->jobs->insert(PROJECT_ID, $job));
}
catch (Exception $e) //or probably better Google_Exception
{
print('Something went wrong');
}