我有一个电话返回BSTR的safearray。我想将其复制到vector<LPOLESTR>
。这样做的正确方法是什么?在这种情况下如何处理内存?
答案 0 :(得分:2)
假设你想要vector<wstring>
,请在评论中进行讨论,如下所示:
SAFEARRAY* sa; // a safearray of BSTR, initialized somehow.
LONG lBound, uBound;
SafeArrayGetLBound(sa, 1, &lBound);
SafeArrayGetUBound(sa, 1, &uBound);
LONG count = uBound - lBound + 1; // bounds are inclusive
BSTR* raw;
SafeArrayAccessData(sa, (void**)&raw);
vector<wstring> v(raw, raw + count);
// or, if you want to assign to an existing vector
vector<wstring> v;
v.assign(raw, raw + count);
// When no longer need "raw".
SafeArrayUnaccessData(sa);
错误处理留给读者练习。