Question

我有一个新手问题。我有查询日期，准备，批准，项目代码，项目名称，品牌名称，总数量，数量当我在数量上输入10时，php会提示我输入然后按插入所有查询怎么做？

    <form method="post" name="increasing" action="<?php echo "increasing.php?id=$id"; ?>">

    <table>
        <h3><center>Increasing</center></h3>

        <tr><td>Date</td><td>:</td><td><input type="date" name="date" style="width: 180px;"></td></tr>
           <tr><td>Prepared By</td><td>:</td><td>
            <select name="pre" style="width: 180px;">
              <option value="">Prepared By</option>
             <?php foreach ($fullname as $fl): ?>

              <option><?=$fl?></option>
            <?php endforeach; ?>
          </select>
           </td></tr>
            <tr><td>Approved By</td><td>:</td><td>
            <select name="app" style="width: 180px;">
              <option value="">Approved By</option>
             <?php foreach ($fullname as $fl): ?>

              <option><?=$fl?></option>
            <?php endforeach; ?>
          </select>
           </td></tr>

        <tr><td>Itemcode</td><td>:</td><td><input type="text" name="itemcode" required="required"  disabled="disabled" value="<?php echo $itemcode; ?>"></td></tr>
        <tr><td>Itemname</td><td>:</td><td><input type="text" name="itemname" required="required" disabled="disabled" value="<?php echo $itemname; ?>"/></td></tr>
        <tr><td>Brandname</td><td>:</td><td><input type="text" name="brandname" required="required" disabled="disabled"  value="<?php echo $brandname; ?>"/></td></tr>
         <tr><td>Total Quantity</td><td>:</td><td><input type="text" name="brandname" readonly="readonly" value="<?php echo $quantity; ?>"/></td></tr>
        <tr><td>Quantity</td><td>:</td><td><input type="number" name="quantity"   value=""/></td></tr>
        <tr><td></td><td></td><td><input type="hidden" name="quantity1" value="<?php echo $quantity; ?>"></td></tr>
        <tr><td></td><td></td><td><input type="submit" name="submit" class="myButton" value="Save"/></td></tr>
    </table>
</form>




    if(isset($_POST['submit'])){

$id = $_GET['id'];
$old = $_POST['quantity'];
$new = $_POST['quantity1'];

$total = $old + $new;



$uiqry = $mysqli->prepare("UPDATE table_inventory SET quantity = ?  WHERE id = ?");

$uiqry->bind_param('ii', $total,$id);

$uiqry->execute();
$uiqry->close();

}


echo "<script>alert('Add');</script>";
echo "<script>window.open('inventory.php', '_self');</script>";

TIA。

Answer 1

在html

中添加此行

<script type="text/javascript" src="http://code.jquery.com/jquery-1.10.2.min.js"></script>

HTML

<input type="text" name="date " value=""/>
<input type="text" name="prepared" value=""/>
<input type="text" name="approved"  value=""/>
<input type="text" name="itemname" value=""/>
<input type="text" name="itemcode" value=""/>
<input type="text" name="totalquantity" value=""/>
<input type="text" name="quantity" value=""/>

Jquery的

$("input[name=quantity]").change(function(e){
if($(this).val() != "")
{
alert("You have added new data");

var date = $("input[name=date]").val();
var prepared= $("input[name=prepared]").val();
var approved= $("input[name=approved]").val();
var itemname= $("input[name=itemname]").val();
var itemcode= $("input[name=itemcode]").val();
var totalquantity= $("input[name=totalquantity]").val();
var quantity= $("input[name=quantity]").val();

// pass the values to insert using ajax like this
jQuery.post("datains.php", {

date :date ,
prepared:prepared,
approved:approved,
itemname:itemname,
itemcode:itemcode,
totalquantity:totalquantity,
quantity:quantity


},  function(data, textStatus){

if (data == 1)
{
alert("Data inserted");
location.reload();

}
else
{
alert("Data not inserted");
return false; 
}
});

}



});

datains.php

// retrive passed values like this
$date= $_POST['date'];
$prepared= $_POST['prepared'];
$approved= $_POST['approved'];
$itemname= $_POST['itemname'];
$itemcode= $_POST['itemcode'];
$totalquantity= $_POST['totalquantity'];
$quantity= $_POST['quantity'];


$con = mysqli_connect("localhost","username","password","dbanme");

$query = //write insert query here;

$result = mysqli_query($con,$query) or die (mysqli_error($con));

if($result)
 echo "1";
else
echo "2";

如何更新，然后在数据库中插入所有记录

1 个答案: