这是正确的方法吗?
DELETE t1, t2, t3, t4 FROM
table1 as t1
INNER JOIN table2 as t2 on t1.id = t2.id
INNER JOIN table3 as t3 on t1.id=t3.id
INNER JOIN table4 as t4 on t1.id=t4.id
WHERE t1.username='%s' AND t1.id='%s'
答案 0 :(得分:10)
是的,这是正确的。它在这里工作正常:
CREATE TABLE table1 (id int, username nvarchar(30));
CREATE TABLE table2 (id int);
CREATE TABLE table3 (id int);
CREATE TABLE table4 (id int);
INSERT INTO table1 VALUES (1, 'Foo'),(2, 'Bar');
INSERT INTO table2 VALUES (1),(2);
INSERT INTO table3 VALUES (1),(2);
INSERT INTO table4 VALUES (1),(2);
SELECT COUNT(*) FROM table1;
2
SELECT COUNT(*) FROM table2;
2
SELECT COUNT(*) FROM table3;
2
SELECT COUNT(*) FROM table4;
2
DELETE t1, t2, t3, t4 FROM
table1 as t1
INNER JOIN table2 as t2 on t1.id = t2.id
INNER JOIN table3 as t3 on t1.id=t3.id
INNER JOIN table4 as t4 on t1.id=t4.id
WHERE t1.username='Foo' AND t1.id='1';
SELECT COUNT(*) FROM table1;
1
SELECT COUNT(*) FROM table2;
1
SELECT COUNT(*) FROM table3;
1
SELECT COUNT(*) FROM table4;
1
如果它不适合您,也许您可以修改此示例以显示您遇到的问题。
答案 1 :(得分:4)
一个简单的解决方法是首先将其写为查询:
SELECT * FROM
table1 as t1
INNER JOIN table2 as t2 on t1.id = t2.id
INNER JOIN table3 as t3 on t1.id=t3.id
INNER JOIN table4 as t4 on t1.id=t4.id
WHERE t1.username='%s' AND t1.id='%s'
如果您得到了预期的结果,只需将* Select **替换为Delete和您的表名。然后它会变成:
Delete t1, t2, t3, t4 From table1 as t1
INNER JOIN table2 as t2 on t1.id = t2.id
INNER JOIN table3 as t3 on t1.id=t3.id
INNER JOIN table4 as t4 on t1.id=t4.id
WHERE t1.username='%s' AND t1.id='%s'
答案 2 :(得分:1)
通过以下方式简化:
DELETE FROM `Table1` t1, `Table2` t2 USING t1, t2
WHERE t1.`id` = t2.`id` AND t1.`id` = 10; <br>
享受:)