我在js中的代码(不起作用)将数据传输到PHP:
function codeAddress() {
var address = document.getElementById('address').value;
geocoder.geocode({ 'address': address}, function(results, status) {
if (status == google.maps.GeocoderStatus.OK) {
map.setCenter(results[0].geometry.location);
var marker = new google.maps.Marker({
map: map,
position: results[0].geometry.location
});
var input = results[0].geometry.location;
var lat = input.lat();
console.log(lat);
/*var lat = input.lat();
var longitude = input.lng();
document.getElementById("wypisz").innerHTML=lat;
request.open("GET", "address.php?lat=" + lat, true);
//var url = "address.php?lat=latitude&lng =longitude";
//document.getElementById("wypisz").innerHTML = results[0].geometry.location.lng;
*/
$.ajax({
type: "GET",
data: "lat=" + lat,
url:"address.php",
success: function(data) { console.log(data) }
})
} else {
alert('Geocode was not successful for the following reason: ' + status);
}
});
并将它们放入PHP文件中:
if(isSet($_GET['lat'])){
echo "param good";
} else {
echo "incorrect";
}
当我print_r
时,它总是显示空数组。
你能帮我改造吗?
这里有更多我的代码,这是我标记特定纬度和经度的地方:
<div id="panel">
Address :
<input id="address" name = "address" type="textbox" value="Warszawa, Pol">
<input type="button" value="wstaw" onclick="codeAddress()" >
</div>
<div id="map-canvas"></div>
在这里我发送信息到php文件:
<input type="submit" id = "ff" value="Send information">
答案 0 :(得分:0)
尝试使用ajax调用,如:
$.ajax({
type:'GET'
url: "address.php?lat="+lat,
success:function(data){
}
});
答案 1 :(得分:0)
var req = new XMLHttpRequest();
req.open("GET", "adress.php", true);
req.onreadystatechange = function() {
if(req.readyState != 4 || req.status != 200)
return;
console.log(req.responseText);
};
req.send("lat=" + lat);
这是一个非常简单的方法,如果你想在错误验证方面有所有的花里胡哨,我强烈建议你使用jquery和$ .get:
$.ajax({
type: "GET",
data: "lat=" + lat,
url:"address.php",
success: function(data) { console.log(data) }
})