Question

我正在尝试在java中编写具有以下输出的java代码。

---JGRASP exez: java Guess
    Is the number 50? H
    Ia the number 75? L
    Is the number 62? L
    Is the number 56? L
    Is the number 53? L
    Is the number 51? C
    It took me 6 guesses!
  ---JGRASP: operation complete.

正如你所看到的那样，它总是减少一半。我花了好几个小时试图找出它没有结果。如果你至少可以给出一个提示，我真的很感激。这是我尝试编写代码的不成功。

import java.util.Scanner;
public class GuessNumber
{
   public static void main(String[]args)
   {
          int num1 = 0,num2 = 100,guesses = 0;
          String answer;
          boolean correct = false;

          Scanner keyboard = new Scanner(System.in);

          do{
              System.out.print("Is the number " + <?> + "? ");       //have no idea
              answer = keyboard.next();

              if(answer.equalsIgnoreCase("C")) {
                    correct = true;
                    guessses++;
               }  
              else if(answer.equalsIgnoreCase("H")){
                    ? = (num1 + num2) / 2;                   //lost here 
                    guesses++;
               } 
              else if(answer.equalsIgnoreCase("L")){
                    ? = (num1 + num2) / 2;                   //lost here
                    guesses++;
               }
           }while(correct == false);

    System.out.print("It took me " + guesses + " guesses!");   
 }

}

Answer 1

public static void main(String[]args)
{
          Random randomNumber = new Random();
          int num1 = 0,num2 = 100,guesses = 0, guess=0;
          String answer;
          boolean correct = false;

          Scanner keyboard = new Scanner(System.in);

          do{
              guess=randomNumber.nextInt(num2-num1) + num1; 

              System.out.print("Is the number " + guess + "? ");       
              answer = keyboard.next();

              if(answer.equalsIgnoreCase("C")) {
                    correct = true;
                    guessses++;
               }  
              else if(answer.equalsIgnoreCase("H")){
                    num1 = guess;              
                    guesses++;
               } 
              else if(answer.equalsIgnoreCase("L")){
                    num2 = guess;                  
                    guesses++;
               }
           }while(correct == false);    
           System.out.print("It took me " + guesses + " guesses!");   
 }

Answer 2

尝试这一点，它的作用是，虽然答案不正确，但它将采用num1（猜测的最小值）和num2（猜测的最大值）并找到它们的平均值。如果数字高于最新猜测，我们将下限设置为最新猜测，如果数字较低，我们将上限设置为最新猜测。

import java.util.Scanner;

public class GuessNumber{

public static void main(String[]args)
{
          int num1 = 0,num2 = 101,guesses = 0, guess=0;
          String answer;
          boolean correct = false;

          Scanner keyboard = new Scanner(System.in);
          do{
              guess=(num1+num2) /2 > 0? (num1+num2) /2:1;

              System.out.print("Is the number " + guess + "? ");       
              answer = keyboard.next();

              if(answer.equalsIgnoreCase("C")) {
                    correct = true;
                    guesses++;
               }  
              else if(answer.equalsIgnoreCase("H")){
                    num1 = guess;              
                    guesses++;
               } 
              else if(answer.equalsIgnoreCase("L")){
                    num2 = guess;                  
                    guesses++;
               }

           }while(correct == false);    
           System.out.print("It took me " + guesses + " guesses!");   
 }

}

使用java中较低，较高，正确的选项来猜测数字

2 个答案: