使用mysql连接概念显示表B中不存在的所有表A记录

Question

表A记录

id | email 
1  | abc@abc.com
2  | xyx@xy.com
3  | kkdk@kk.com
4  | 333@abc.com

表B记录

id | email
1  | abc@abc.com
3  | kkdk@kk.com

现在结果应该是

id | email
2  | xyx@xy.com
4  | 333@abc.com

如何使用连接执行此操作？

Answer 1

尝试类似：

SELECT 
t1.*
FROM tableA as t1
LEFT JOIN tableB t2 ON t1.email=t2.email
WHERE t2.id IS NULL

Answer 2

试试这个：

select distinct(a.id), a.email from table1 a inner join table2 b
on a.id not in (select id from table2)

fiddle

Answer 3

尝试左连接并检查tableB id为null的位置。

select tableA.* from tableA left join tableB on tableA.email = tableB.email
where tableB.id is null