取消谷歌加登录按钮

Question

在Twitter中，当用户按下取消按钮时，它会被重定向到此URL：

URL/verify?denied=TOKEN

因此，您可以通过网址中的denied来确定它。

在google +登录中，有没有办法检测登录页面中的取消按钮或检测javascript或jquery的关闭按钮？

Answer 1

在回调函数中，如果用户拒绝同意对话框，则会返回错误代码。

检查access_denied的示例回调，表示用户拒绝了同意对话框：

  function onSignInCallback(authResult) {
    if (authResult['access_token']) {
      // success
    } else if (authResult['error']) {
      if (authResult['error'] == 'immediate_failed'){
        // This is perfectly normal, the user reached the site and was not logged in
        // However, if the user should be signed in on this page, it would be
        // appropriate to have an error here
      }
      if (authResult['error'] == 'access_denied'){
        // The user cancelled out of the dialog.
      }

      // There was an error, which means the user is not signed in.
      // As an example, you can handle by writing to the console:
      console.log('There was an error: ' + authResult['error']);
    }
    console.log('authResult', authResult);
  };