我有一个博主博客,但我的API有点迷失。我想知道是否可以创建一个列出我博客的所有帖子的页面。
我在互联网上找到了一些答案,但大部分答案都不再适用:(
我有另一个问题:可以在不使用javascript的情况下使用数据库吗?我可能错了,但我认为大多数小部件都使用AJAX(它调用一些JSON来获取所有信息并在JS中显示它们)。
谢谢!
答案 0 :(得分:3)
要列出所有博客帖子,您无需访问Blogger API。使用博客的Feed和一小段Javascript就可以为您做到这一点。
可以在这里看到工作示例: http://codepen.io/yaqoob/pen/GqJDy/
以下是Javascript代码:
<script type="text/javascript">
var postTitle=new Array();var postUrl=new Array();var postMp3=new Array();var postDate=new Array();var postYear=new Array();var postMonth=new Array();var postYearMonth=new Array();var postYearMonth2=new Array();var postTanggal=new Array();var postLabels=new Array();var postBaru=new Array();var sortBy="titleasc";var tocLoaded=false;var numChars=250;var postFilter="";var numberfeed=0;var month2=["January","February","March","April","May","June","July","August","September","October","November","December"];function loadtoc(a){function b(){if("entry" in a.feed){var d=a.feed.entry.length;numberfeed=d;ii=0;for(var h=0;h<d;h++){var m=a.feed.entry[h];var e=m.title.$t;var l=m.published.$t.substring(0,10);var p=m.published.$t.substring(5,7);var g=m.published.$t.substring(8,10);var n=month2[parseInt(p,10)-1]+" "+m.published.$t.substring(0,4);var c="/"+m.published.$t.substring(0,4)+"_"+p+"_01_archive.html";var j;for(var f=0;f<m.link.length;f++){if(m.link[f].rel=="alternate"){j=m.link[f].href;break}}var o="";for(var f=0;f<m.link.length;f++){if(m.link[f].rel=="enclosure"){o=m.link[f].href;break}}postTitle.push(e);postDate.push(l);postUrl.push(j);postYearMonth.push(n);postYearMonth2.push(c);postTanggal.push(g)}}}b();displayToc2();document.write('<br/><a href="http://feeds2.feedburner.com/YourFeed" style="font-size: 11px; text-decoration:none; color: #616469;">Subscribe to Our RSS Feed and Get all the updates On the Fly</a></br/>')}function displayToc2(){var a=0;var b=0;while(b<postTitle.length){temp1=postYearMonth[b];document.write("<p/>");document.write('<p><a href="'+postYearMonth2[b]+'">'+temp1+"</a></p><ul>");firsti=a;do{document.write("<li>");document.write("["+postTanggal[a]+'] <a href="'+postUrl[a]+'">'+postTitle[a]+"</a>");document.write("</li>");a=a+1}while(postYearMonth[a]==temp1);b=a;document.write("</ul>");if(b>postTitle.length){break}}};
</script>
以下是Javascript回调。
<script src="http://domain.blogspot.com/feeds/posts/default?max-results=500&alt=json-in-script&callback=loadtoc"></script>
将博客链接替换为您自己的链接。
答案 1 :(得分:2)
您好,我找到最佳解决方案
制作HTMl JAVA / SCript小部件
简单发布代码,效果很好
<div><ul id="postList12"></ul></div>
<script type="text/javascript">
var startIndex = 1;
var maxResults = 100;
function sendQuery12()
{
var scpt = document.createElement("script");
scpt.src = "/feeds/posts/summary?alt=json&callback=processPostList12&start-index=" + startIndex + "&max-results=" + maxResults;
document.body.appendChild(scpt);
}
function processPostList12(root)
{
var elmt = document.getElementById("postList12");
if (!elmt)
return;
var feed = root.feed;
if (feed.entry.length > 0)
{
for (var i = 0; i < feed.entry.length; i++)
{
var entry = feed.entry[i];
var title = entry.title.$t;
for (var j = 0; j < entry.link.length; j++)
{
if (entry.link[j].rel == "alternate")
{
var url = entry.link[j].href;
if (url && url.length > 0 && title && title.length > 0)
{
var liE = document.createElement("li");
var a1E = document.createElement("a");
a1E.href = url;
a1E.textContent = title;
liE.appendChild(a1E);
elmt.appendChild(liE);
}
break;
}
}
}
if (feed.entry.length >= maxResults)
{
startIndex += maxResults;
sendQuery12();
}
}
}
sendQuery12();