Question

在我的csv计划开始时：

import csv     # imports the csv module
import sys      # imports the sys module

f = open('Address Book.csv', 'rb') # opens the csv file
try:
    reader = csv.reader(f)  # creates the reader object
    for row in reader:   # iterates the rows of the file in orders
        print (row)    # prints each row
finally:
    f.close()      # closing

错误是：

    for row in reader:   # iterates the rows of the file in orders
_csv.Error: iterator should return strings, not bytes (did you open the file in text mode?)

Answer 1

而不是这个（和其余的）：

f = open('Address Book.csv', 'rb')

这样做：

with open('Address Book.csv', 'r') as f:
    reader = csv.reader(f) 
    for row in reader:
        print(row)

上下文管理器意味着您不需要finally: f.close()，因为它会在出错时或退出上下文时自动关闭文件。

Answer 2

这个（重复？）问题csv.Error: iterator should return strings, not bytes中的解决方案帮助了我：

f = open('Address Book.csv', "rt")

或

with open('Address Book.csv', "rt") as f:

或（使用gzip）

import gzip
f = gzip.open('Address Book.csv', "rt")

或

import gzip
gzip.open('Address Book.csv', "rt") as f:

_csv.Error：迭代器应该返回字符串，而不是字节（你是否在文本模式下打开文件？）

2 个答案: