Question

我有一个数据库，记录每个收银员每小时的交易次数。

列名：

NAME        00  01  02  03  04  05  06 07  08  09  10  11  12  13  14  15  16  17  18  19  20  21  22  23 DATE

<00> 00将是午夜，01将是凌晨1点，18点将是下午6点，依此类推。

平均行看起来像这样：

    John Doe  0  0  0  0  0   0   0   0   0   0 26 24 32  0  0  0  0  0  0  0  0  0  0  0  02/23/2014 
    John Doe  0  0  0  0  0  23  43  25  36  42  0  0  0  0  0  0  0  0  0  0  0  0  0  0  02/22/2014

我正在尝试在同一查询中获取不同日期的不同列。

例如，假设我想要2014年2月22日05,06,07,08,09和2014年2月23日10,11,12为John Doe。这将是John Doe整个周末所做的总交易时间。

让我们说John Doe本月大部分时间都有争议。我怎么能得到一条线只显示2014年2月22日的05,06,07,08和09小时以及2014年2月23日的10,11,12小时以及其他日期/小时？

我试过了：

SELECT cashier.name AS NAME, 
(SELECT cashier.05 FROM cashier AS t WHERE date = '2014-02-22' AND t.name = cashier.name) as '05', 
(SELECT cashier.06 FROM cashier AS t WHERE date = '2014-02-22' AND t.name = cashier.name) as '06', 
(SELECT cashier.07 FROM cashier AS t WHERE date = '2014-02-22' AND t.name = cashier.name) as '07',
(SELECT cashier.08 FROM cashier AS t WHERE date = '2014-02-22' AND t.name = cashier.name) as '08',
(SELECT cashier.09 FROM cashier AS t WHERE date = '2014-02-22' AND t.name = cashier.name) as '09', 
(SELECT cashier.10 FROM cashier AS t WHERE date = '2014-02-23' AND t.name = cashier.name) as '10',
(SELECT cashier.11 FROM cashier AS t WHERE date = '2014-02-23' AND t.name = cashier.name) as '11',
(SELECT cashier.12 FROM cashier AS t WHERE date = '2014-02-23'  AND t.name = cashier.name) as '12'
FROM cashier
WHERE NAME = 'John Doe'

Answer 1

SELECT f.name , f.17,
(SELECT t.05 FROM cashier AS t WHERE f.name = t.name AND t.date = '2014-02-22') AS '05',
(SELECT t.06 FROM cashier AS t WHERE f.name = t.name AND t.date = '2014-02-22') AS '06',
(SELECT t.07 FROM cashier AS t WHERE f.name = t.name AND t.date = '2014-02-22') AS '07',
(SELECT t.08 FROM cashier AS t WHERE f.name = t.name AND t.date = '2014-02-22') AS '08',
(SELECT t.09 FROM cashier AS t WHERE f.name = t.name AND t.date = '2014-02-22') AS '09',
(SELECT t.10 FROM cashier AS t WHERE f.name = t.name AND t.date = '2014-02-23') AS '10',
(SELECT t.11 FROM cashier AS t WHERE f.name = t.name AND t.date = '2014-02-23') AS '11',
(SELECT t.12 FROM cashier AS t WHERE f.name = t.name AND t.date = '2014-02-23') AS '12'
FROM cashier AS f
WHERE date = '2014-02-22' 
AND f.18 > 0");

Mysql - 特定日期的特定列

1 个答案: