Question

# File function2.py

def f():
  print("I am f")
  return("return f")

if __name__ == "__main__":
  print("print(f) gives", end=": "); print(f)
  print("f        gives", end=": "); f
  print("f()      gives", end=": "); f()

如果您运行代码python function2.py，则会有

print(f) gives: <function f at 0x026CD6F0>
f        gives: f()      gives: I am f

但是，如果以交互方式键入并执行代码，您将拥有：

>>> def f():
...   print("I am f")
...   return("return f")
...
>>> if __name__ == "__main__":
...   print("print(f) gives", end=": "); print(f)
...   print("f        gives", end=": "); f
...   print("f()      gives", end=": "); f()
...
print(f) gives: <function f at 0x025BD6F0>
f        gives: <function f at 0x025BD6F0>
f()      gives: I am f
'Return f'
>>>

这是一个错误吗？

Answer 1

@DSM是对的。 ;背后的东西是一个新的陈述。

你写的是

print("print(f) gives", end=": ")
print(f)
print("f        gives", end=": ")
f # this causes the program to just go over it and do nothing but in the REPL this is printing f
print("f()      gives", end=": ")
f()

REPL =阅读评估Print Loop =交互式解释器= >>>

所以你做了

>>> f # print(f) in REPL
<function f at 0x025BD6F0>
>>> f() # print(f()) in REPL # = print("I am f"); print("return f")
I am f
'return f'

因此，REPL在程序中输入的每一行都附加print()。

这就是输出的原因。如果您想让它保持一致，请使用print。

python 3.3在交互式和程序模式下的结果不一致

1 个答案: