Question

所以我试图使用三维数组打印出七段显示器：

我偶然发现了这篇文章，解释了七段显示器的阵列结构： http://cboard.cprogramming.com/c-programming/94140-seven-segment-display.html

这就是我想要打印出来的内容：

char array[9][10][20]

但我似乎无法弄清楚如何将其打印出来。此外，我很难理解如何打印七段数字中的一个（例如只是'5'）？

我认为我需要三个for循环，但我不确定如何实现第三个循环。我发现的任何例子都只有2d，我可以得到，但最后一个维度让我感到困惑。

非常感谢任何帮助！

Answer 1

不要过度思考它。这是一个例子：

#include <stdio.h>

char array[9][10][20] =
     {
          {" ### ","    "," ### "," ### ","     "," ### "," ### "," ### "," ### "," ### "},
          {"#   #","   #","    #","    #","#   #","#    ","#    ","    #","#   #","#   #"},
          {"#   #","   #","    #","    #","#   #","#    ","#    ","    #","#   #","#   #"},
          {"#   #","   #","    #","    #","#   #","#    ","#    ","    #","#   #","#   #"},
          {"     ","    "," ### "," ### "," ### "," ### "," ### ","     "," ### "," ### "},
          {"#   #","   #","#    ","    #","    #","    #","#   #","    #","#   #","    #"},
          {"#   #","   #","#    ","    #","    #","    #","#   #","    #","#   #","    #"},
          {"#   #","   #","#    ","    #","    #","    #","#   #","    #","#   #","    #"},
          {" ### ","    "," ### "," ### ","     "," ### "," ### ","     "," ### "," ### "},
     };

int main(void) {
  int ii, jj, kk;

  // printing '3':

  for(ii = 0; ii<9; ii++) {
    printf("%s\n", array[ii][3]);
  }
}

输出：

 ### 
    #
    #
    #
 ### 
    #
    #
    #
 ###

为什么这样做？

首先，让我们看看用于创建段的数组。这是一个9x10x20的字符数组。

事实上，虽然最后一个维度设置为20，但它完全由长度为6的字符串组成（5+1用于终止'\0'）。要打印出单个数字，您只想打印属于该数字的字符串 - 上面的例子对数字3进行了打印。

如果要打印更长的数字字符串会变得更加棘手，因为您必须以每行为基础遍历每个数字。您可以通过以下方式使用数字12345：

#include <stdio.h>
#include <string.h>

char array[9][10][20] =
     {
          {" ### ","    "," ### "," ### ","     "," ### "," ### "," ### "," ### "," ### "},
          {"#   #","   #","    #","    #","#   #","#    ","#    ","    #","#   #","#   #"},
          {"#   #","   #","    #","    #","#   #","#    ","#    ","    #","#   #","#   #"},
          {"#   #","   #","    #","    #","#   #","#    ","#    ","    #","#   #","#   #"},
          {"     ","    "," ### "," ### "," ### "," ### "," ### ","     "," ### "," ### "},
          {"#   #","   #","#    ","    #","    #","    #","#   #","    #","#   #","    #"},
          {"#   #","   #","#    ","    #","    #","    #","#   #","    #","#   #","    #"},
          {"#   #","   #","#    ","    #","    #","    #","#   #","    #","#   #","    #"},
          {" ### ","    "," ### "," ### ","     "," ### "," ### ","     "," ### "," ### "},
     };

int main(void) {
  int ii, jj, kk;

  // printing '3':

  for(ii = 0; ii<9; ii++) {
    printf("%s\n", array[ii][3]);
  }
  // print '12345'
  int numToPrint = 12345;

  char numBuf[20];
  sprintf(numBuf, "%d", numToPrint);

  for(ii=0; ii<9; ii++) {
    for(jj=0; jj < strlen(numBuf); jj++) {
      printf("%s ", array[ii][numBuf[jj]-'0']);
    }
    printf("\n");
  }
}

第二部分的输出：

      ###   ###         ###  
   #     #     # #   # #     
   #     #     # #   # #     
   #     #     # #   # #     
      ###   ###   ###   ###  
   # #         #     #     # 
   # #         #     #     # 
   # #         #     #     # 
      ###   ###         ###

注意 - 我使用sprintf函数将整数转换为字符串 - 然后我可以通过查看字符串中的每个字符并减去'0'来找到每个相应的数字。在“真实”代码中，您当然会检查您是否没有超出数组边界，并且您可能希望包含一个小数点的字符串以及+和-符号来制作一些东西更灵活 - 但我希望你能从中得到这个想法。

Answer 2

我不确定你想要什么，但这是一种显示想要号码的方法。

int numberToDisplay = 5;

for (int i = 0; i < 9; i++)
    fprintf(stdout, "%s\n", array[i][numberToDisplay];

Answer 3

在最高级别，我们有：

array =
     {
          {" ### ","     "," ### "," ### ","     "," ### "," ### "," ### "," ### "," ### "},
          {"#   #","    #","    #","    #","#   #","#    ","#    ","    #","#   #","#   #"},
          {"#   #","    #","    #","    #","#   #","#    ","#    ","    #","#   #","#   #"},
          {"#   #","    #","    #","    #","#   #","#    ","#    ","    #","#   #","#   #"},
          {"     ","     "," ### "," ### "," ### "," ### "," ### ","     "," ### "," ### "},
          {"#   #","    #","#    ","    #","    #","    #","#   #","    #","#   #","    #"},
          {"#   #","    #","#    ","    #","    #","    #","#   #","    #","#   #","    #"},
          {"#   #","    #","#    ","    #","    #","    #","#   #","    #","#   #","    #"},
          {" ### ","     "," ### "," ### ","     "," ### "," ### ","     "," ### "," ### "},    
     };

此数组有9个元素，对应于SSD数字ASCII艺术的行。例如：

array[2] =
    {
        "#   #", /* 3rd row of digit '0' */
        "    #", /* 3rd row of digit '1' */
        "    #", /* 3rd row of digit '2' */
        "    #", /* 3rd row of digit '3' */
        "#   #", /* 3rd row of digit '4' */
        "#    ", /* 3rd row of digit '5' */
        "#    ", /* 3rd row of digit '6' */
        "    #", /* 3rd row of digit '7' */
        "#   #", /* 3rd row of digit '8' */
        "#   #", /* 3rd row of digit '9' */
    };

索引此数组将选择要从中打印第3行的数字。因此，要打印多个数字，我们需要以下内容：

char array[9][10][20] = 
     {
          {" ### ","     "," ### "," ### ","     "," ### "," ### "," ### "," ### "," ### "},
          {"#   #","    #","    #","    #","#   #","#    ","#    ","    #","#   #","#   #"},
          {"#   #","    #","    #","    #","#   #","#    ","#    ","    #","#   #","#   #"},
          {"#   #","    #","    #","    #","#   #","#    ","#    ","    #","#   #","#   #"},
          {"     ","     "," ### "," ### "," ### "," ### "," ### ","     "," ### "," ### "},
          {"#   #","    #","#    ","    #","    #","    #","#   #","    #","#   #","    #"},
          {"#   #","    #","#    ","    #","    #","    #","#   #","    #","#   #","    #"},
          {"#   #","    #","#    ","    #","    #","    #","#   #","    #","#   #","    #"},
          {" ### ","     "," ### "," ### ","     "," ### "," ### ","     "," ### "," ### "},    
     };

int main(void) {
    int i, j;
    char number[] = "345";
    for (i = 0; i < 9; i++) {                         /* For each row...*/
        for (j = 0; number[j] != '\0'; j++) {         /* Print the nth row of each digit */
            printf("%s ", array[i][number[j] - '0']);
        }
        putchar('\n');
    }
    return 0;
}

在c中打印出3D阵列

3 个答案: