Question

我对此构建问题感到困惑。以下案例成功构建。

案例1

`

public Insets getOpticalInsets() {
 System.out.println(" hello ");
 return Insets.NONE;
}

`

案例2

`

public Insets getOpticalInsets() { 
{
 return Insets.NONE;
}
}

`

但是以下情况失败并将错误消息显示为“返回不可用的类型插入”

案例失败

`

public Insets getOpticalInsets() { 
{
 System.out.println(" hello ");
 return Insets.NONE;
}
}

`

我搜索了类似的错误但找不到任何有用的内容。有人可以解释一下这究竟是什么错误。

完成日志消息

frameworks / base / graphics / java / android / graphics / drawable / Drawable.java:601：错误110：方法android.graphics.drawable.Drawable.getOpticalInsets返回不可用的类型Insets

源文件：

`

package android.graphics.drawable;

import android.graphics.Insets;
import android.os.Trace;
import org.xmlpull.v1.XmlPullParser;
import org.xmlpull.v1.XmlPullParserException;

import android.content.res.Resources;
import android.content.res.TypedArray;
import android.graphics.Bitmap;
import android.graphics.BitmapFactory;
import android.graphics.Canvas;
import android.graphics.ColorFilter;
import android.graphics.NinePatch;
import android.graphics.PixelFormat;
import android.graphics.PorterDuff;
import android.graphics.PorterDuffColorFilter;
import android.graphics.Rect;
import android.graphics.Region;
import android.os.Build;
import android.util.AttributeSet;
import android.util.DisplayMetrics;
import android.util.StateSet;
import android.util.TypedValue;
import android.util.Xml;

import java.io.IOException;
import java.io.InputStream;
import java.lang.ref.WeakReference;
import java.util.Arrays;


public abstract class Drawable {
    private static final Rect ZERO_BOUNDS_RECT = new Rect();

    private int[] mStateSet = StateSet.WILD_CARD;
    private int mLevel = 0;
    private int mChangingConfigurations = 0;
    private Rect mBounds = ZERO_BOUNDS_RECT;  
    private WeakReference<Callback> mCallback = null;
    private boolean mVisible = true;

    private int mLayoutDirection;


    private String mImagePath;



    public Insets getOpticalInsets() {        
            {
                System.out.println(" hello ");
                return Insets.NONE;
            }
    }



}

`

Java构建错误“返回不可用类型”

0 个答案: