Question

如果磁盘（已下载文件的大小）与服务器上的大小（对于网址）不同，如何检索网址名称？

import os, glob, urllib

urls_file = open ('urls.txt','r')
urls = urls_file.read().splitlines()
urls_file.close()

for u in urls:
    data = urllib.urlopen(u)
    size_server = data.info()['Content-Length']   

files_disk = glob.glob('*.jpg')
for f in files_disk:
    size_disk = os.stat(f).st_size

在那之后，我不知道如何继续，请帮助。

Answer 1

所以我假设你在这里提取图像，如果Content-Length标题与磁盘上的文件大小不匹配，你想得到这些网址的列表。

试试这个：

url_size = {}

with open('urls.txt') as f:
   for line in f:
      url = line.strip()
      if len(url):
          try:
              data = urllib.urlopen(url)
              url_size[os.path.basename(urlparse(url).path)] = data.info()['Content-Length']
          except:
              print('Cannot fetch information for: {}'.format(url))


for fname in glob.glob('*.jpg'):
    try:
        disk_size = os.stat(fname).st_size
        if url_size.get(fname) != disk_size:
            print('{} does not match fetched size of {}'.format(fname, url_size.get(fname))
    except:
        print('Cannot fetch file size for {}'.format(fname))

不要忘记导入库。

python中列表之间的比较

1 个答案: