Question

我需要运行以下3选择查询：

SELECT profile_gender AS Gender, COUNT(*) AS Users FROM login GROUP BY profile_gender;

SELECT profile_gender AS Gender, COUNT(*) AS Users FROM login WHERE profile_createdate > DATE_SUB(CURDATE(), INTERVAL 1 DAY) GROUP BY profile_gender;

SELECT profile_gender AS Gender, COUNT(*) AS Users FROM login WHERE profile_createdate > DATE_SUB(CURDATE(), INTERVAL 7 DAY) GROUP BY profile_gender;

profile_gender为0或1，并且位于同一列中。是否可以在一个查询中获取此信息？它有点超出了我目前的查询能力。

感谢

Answer 1

在实际字段列表中进行计数：

SELECT profile_gender AS Gender,
    SUM(profile_createdate > (CURDATE() - INTERVAL 1 DAY)) AS Day1,
    SUM(profile_createdate > (CURDATE() - INTERVAL 7 DAY)) AS Day7,
    COUNT(profile_createdate) AS Total
FROM login
GROUP BY profile_gender

>比较的布尔结果将通过mysql转换为普通整数0或1，然后可以SUM()编辑。

Answer 2

您可以使用条件聚合执行此操作：

SELECT profile_gender AS Gender, COUNT(*) AS Users,
       sum(profile_createdate > DATE_SUB(CURDATE(), INTERVAL 1 DAY) as cnt_1day,
       sum(profile_createdate > DATE_SUB(CURDATE(), INTERVAL 7 DAY) as cnt_7day
FROM login
GROUP BY profile_gender;

MySQL - 尝试将3个SELECTS合二为一

2 个答案: