如何找到元素?

时间:2014-03-02 04:08:26

标签: java servlets set

如何检查集合中的元素是否存在?

public class Account
{
    public Account(String username, String password, String lastname, String firstname){
        this.username = username;
        this.password = password;
        this.firstname = firstname;
        this.lastname = lastname;
    }

    public String getUsername() {
        return username;
    }

    public String getPassword() {
        return password;
    }

    public String getFirstname() {
        return firstname;
    }

    public String getLastname() {
        return lastname;
    }


    private String username;
    private String password;
    private String firstname;
    private String lastname;
public boolean equals(Object obj)
    {
        boolean result = false;
        if (obj != null && obj instanceof Account)
        {
            Account p = (Account)obj;
            if ( getUsername().equals(p.getUsername()) 
              && getPassword() == p.getPassword() )
            {
                result = true;
            }
        }
        return result;
    }
}

我的Servlet

Set<Account> acc = new HashSet<Account>();

    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        doPost(request, response);
    }

    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        response.setContentType("text/html");
        acc.add(new Account("test1", "pass123", "Boom", "Bang"));
            acc.add(new Account("test2", "pass123", "Beam", "Beng"));
        PrintWriter out = response.getWriter();
        String username = "";
        String password = "";


    if(request.getParameter("Username") != null){
        username = request.getParameter("Username");
    }
    if(request.getParameter("Password") != null){
        password = request.getParameter("Password");
    }

    Account act1 = new Account(username, password, "", "","");

            /*
            Works only on hard code
            Account act1 = new Account("test1", "pass123", "", "","");
            */

        out.print("<html>");
        out.print("<head><link href='layoutit/css/bootstrap.min.css' rel='stylesheet'>"
                + "<link href='layoutit/css/style.css' rel='stylesheet'>");
        out.print("<title></title>");
        out.print("</head>");
        out.print("<body");
        for (Account p : acc)
        {
            if(p.equals(act1){

                out.print("<h3>Click <a href='displayuser.html'>here</a> to continue.</h3>");
            }
            else{
                out.print("<h1>Invalid user account entered.Click <a href='index.html'>here</a> to login.</h1>");
            }
        }
        out.print("</body>");
        out.print("</hmtl>");
        out.close();
    }

2 个答案:

答案 0 :(得分:1)

Set有一个'contains'方法以及任何扩展/实现Collection的类型。您必须小心为您的帐户类型实现equals和hashcode。您可以在Object type文档中找到详细信息。

答案 1 :(得分:1)

equals(Object)课程中覆盖Account(正确实施),然后执行:

boolean containsAccount = acc.contains(some_account)

其中some_accountinstanceof Account