Question

我正在尝试将python 3.3中的smtp发送给文本文件中列出的收件人。我收到的错误是：
session.sendmail(sender, recipient, msg.as_string()) smtplib.SMTPRecipientsRefused: {}

sendmail中的错误在哪里？谢谢！

以下完整代码：

#!/usr/bin/python
import os, re
import sys
import smtplib

from email.mime.image import MIMEImage
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText

mails = open('/path/emails.txt','r+')
mailList = mails.read()
mailList = [i.strip() for i in mails.readlines()] 
directory = "/path/Desktop/"

SMTP_SERVER = 'smtp.gmail.com'
SMTP_PORT = 587

sender = 'Sender@gmail.com'
password = "Sender'sPassword"
recipient = [i.strip() for i in mails.readlines()] 
subject = 'Python (-++-) Test'
message = 'Images attached.'

def main():
    msg = MIMEMultipart()
    msg['Subject'] = 'Python (-++-) Test'
    msg['To'] = recipient
    msg['From'] = sender

    files = os.listdir(directory)
    pngsearch = re.compile(".png", re.IGNORECASE)
    files = filter(pngsearch.search, files)
    for filename in files:
        path = os.path.join(directory, filename)
        if not os.path.isfile(path):
            continue

         img = MIMEImage(open(path, 'rb').read(), _subtype="png")
         img.add_header('Content-Disposition', 'attachment', filename=filename)
         msg.attach(img)

    part = MIMEText('text', "plain")
    part.set_payload(message)
    msg.attach(part)

    session = smtplib.SMTP(SMTP_SERVER, SMTP_PORT)

    session.ehlo()
    session.starttls()
    session.ehlo
    session.login(sender, password)

    session.sendmail(sender, recipient, msg.as_string())
    session.quit()

if __name__ == '__main__':
    main()

Answer 1

您想要仔细检查收件人代码。看起来你试图不止一次地使用文件的内容，这是行不通的 - 文件对象应理解为流，而不是数据块，所以一旦你完成{{1或者f.read()一次，该流是空的，所以第二次这样做会产生一个空列表。您应该通过打印[i.strip() for i in mails.readlines()]

自行检查

然后试试这个：

recipient

现在你应该有一个填充的收件人列表，然后到下一期！

在python 3.3中从.txt发送电子邮件给收件人

1 个答案: