Question

您正在使用Java EE 7.代码具有以下结构。

模型 - ＆gt;实体豆

业务 - ＆gt;模型的服务类（每个包含一个EntityManager）

演示文稿 - ＆gt;在服务上使用@EJB命名为SessionScoped Beans

当我用1个服务/ EntityManager测试程序时一切正常但现在当我添加第二个服务类时我得到了这个错误：

>

SEVERE:   Exception while invoking class org.glassfish.persistence.jpa.JPADeployer prepare method
SEVERE:   javax.persistence.PersistenceException: Exception [EclipseLink-28018] (Eclipse Persistence Services - 2.5.0.v20130507-3faac2b): org.eclipse.persistence.exceptions.EntityManagerSetupException
Exception Description: Predeployment of PersistenceUnit [watchuwantPU] failed.
Internal Exception: Exception [EclipseLink-7250] (Eclipse Persistence Services - 2.5.0.v20130507-3faac2b): org.eclipse.persistence.exceptions.ValidationException
Exception Description: [class model.Tag] uses a non-entity [class java.lang.String] as target entity in the relationship attribute [field beschreibung].
    at org.eclipse.persistence.internal.jpa.EntityManagerSetupImpl.createPredeployFailedPersistenceException(EntityManagerSetupImpl.java:1950)
    at org.eclipse.persistence.internal.jpa.EntityManagerSetupImpl.predeploy(EntityManagerSetupImpl.java:1941)
    at org.eclipse.persistence.jpa.PersistenceProvider.createContainerEntityManagerFactory(PersistenceProvider.java:322)
    at org.glassfish.persistence.jpa.PersistenceUnitLoader.loadPU(PersistenceUnitLoader.java:199)
    at org.glassfish.persistence.jpa.PersistenceUnitLoader.<init>(PersistenceUnitLoader.java:107)
    at org.glassfish.persistence.jpa.JPADeployer$1.visitPUD(JPADeployer.java:223)
    at org.glassfish.persistence.jpa.JPADeployer$PersistenceUnitDescriptorIterator.iteratePUDs(JPADeployer.java:510)
    at org.glassfish.persistence.jpa.JPADeployer.createEMFs(JPADeployer.java:230)
    at org.glassfish.persistence.jpa.JPADeployer.prepare(JPADeployer.java:168)

的persistence.xml

<persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence"    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="watchuwantPU" transaction-type="JTA">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<jta-data-source>watchuwant</jta-data-source>
<exclude-unlisted-classes>false</exclude-unlisted-classes>
<properties>
  <property name="javax.persistence.schema-generation.database.action" value="drop-and-create"/>
</properties>
</persistence-unit>
</persistence>

FilmService.java

@Stateless

公共类FilmService {

@PersistenceContext(name="watchuwantPU", unitName = "watchuwantPU")
private EntityManager em;

public void add(Film Film){
    em.persist(Film);
}

public List<Film> findAll(){
    return em.createQuery("select f from Film f order by f.id").getResultList();
}
}

LizenzPM.java

@SessionScoped
@Named

public class LizenzPM implements Serializable{

private String lizenzgeber;
private String lizenztyp;
private String lizenzurl;
private Date erteiltAm;


@EJB
private LizenzService service;

Film.java实体

@Entity
public class Film implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
private String titel;

@OneToMany(mappedBy = "parent", cascade=CascadeType.ALL, orphanRemoval=true)
private List<Tag> tags = new LinkedList<>();

Tag.class实体

@Entity
public class Tag implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
@ManyToOne(optional = false)
private String beschreibung;
private Film parent;

Answer 1

我认为持久性单元名称为watchuwantPU，而不是LizenzService。检查@PersistenceContext注释。

持久性单元错误更多2个EntityManager s1持久性单元？

1 个答案: