Question

我有一个记录实体的每个状态变化的表

id      recordTime        Status
ID1 2014-03-01 11:33:00 Disconnected  
ID1 2014-03-01 12:13:00 Connected  
ID2 2014-03-01 12:21:00 Connected  
ID1 2014-03-01 12:24:00 Disconnected  
ID1 2014-03-01 12:29:00 Connected  
ID2 2014-03-01 12:40:00 Disconnected  
ID2 2014-03-01 13:03:00 Connected  
ID2 2014-03-01 13:13:00 Disconnected  
ID2 2014-03-01 13:29:00 Connected  
ID1 2014-03-01 13:30:00 Disconnected

我需要计算总的非活动时间，即给定时间窗口内每个ID的“已连接”和“最后断开”状态之间的时间。

对于上表和时间范围2014-03-01 11:00:00至2014-03-01 14:00:00输出应为：

ID  InactiveTime
ID1  01:15:00
ID2  02:00:00

Answer 1

这就是我理解您的问题SQL Fiddle

的方法

select id, sum(diff) as inactive
from (
    select
        recordtime,
        recordTime -
            lag(recordTime, 1, recordTime)
            over(
                partition by id
                order by recordTime
            )
        as diff,
        status,
        id
    from t
) s
where status = 'Connected'
group by id
order by id
;
 id | inactive 
----+----------
  1 | 00:45:00
  2 | 00:39:00

你能解释一下你想要的输出吗？

Answer 2

特殊的困难是不要错过超出时间范围的时间假设任何给定id的下一行总是具有相反的状态使用列名ts代替recordTime：

WITH span AS (
   SELECT '2014-03-01 13:00'::timestamp AS s_from  -- start of time range
        , '2014-03-01 14:00'::timestamp AS s_to    -- end of time range
   )
, cte AS (
   SELECT id, ts, status, s_to
        , lead(ts, 1, s_from) OVER w AS span_start
        , first_value(ts)     OVER w AS last_ts
   FROM   span s
   JOIN   tbl  t ON t.ts BETWEEN s.s_from AND s.s_to
   WINDOW w AS (PARTITION BY id ORDER BY ts DESC)
   )
SELECT id, sum(time_disconnected)::text AS total_disconnected
FROM  (
   SELECT id, ts - span_start AS time_disconnected
   FROM   cte
   WHERE  status = 'Connected'

   UNION  ALL  
   SELECT id, s_to - ts
   FROM   cte
   WHERE  status = 'Disconnected'
   AND    ts = last_ts
   ) sub
GROUP  BY 1
ORDER  BY 1;

按要求返回间隔在所选时间范围内没有条目的ID不会显示。你必须另外查询它们。

SQL Fiddle.
注意：我将结果total_disconnected投射到小提琴中text，因为类型interval以可怕的格式显示。

在所选时间范围内添加无条目的ID

^{评论中的每个请求。}
添加到上面的查询（在最终ORDER BY 1之前）：

...
UNION  ALL
SELECT id, total_disconnected
   FROM  (
   SELECT DISTINCT ON (id)
          t.id, t.status, (s.s_to - s.s_from)::text AS total_disconnected
   FROM   span     s
   JOIN   tbl      t ON t.ts < s.s_from  -- only from before time range
   LEFT   JOIN cte c USING (id)
   WHERE  c.id IS NULL         -- not represented in selected time frame
   ORDER  BY t.id, t.ts DESC   -- only the latest entry
   ) sub
WHERE  status = 'Disconnected' -- only if disconnected
ORDER  BY 1;

SQL Fiddle.

现在，只有在或所选时间范围内没有参赛作品的ID才会显示。

Answer 3

select id , sum(diff) inactif_time
from
(
SELECT id, "recordTime", "Status" ,LEAD("recordTime") OVER(PARTITION BY id order by "recordTime" ),LEAD("recordTime") OVER(PARTITION BY id order by "recordTime" ) - "recordTime" diff
  FROM my_table
) B 
where "Status" = 'Disconnected'
group by id

但它输出：

"ID1";"00:45:00"
"ID2";"00:39:00"

行之间的时差之和

3 个答案:

在所选时间范围内添加无条目的ID