如何解析xsd:dateTime格式?

时间:2010-02-06 00:11:10

标签: python xml

xsd:dateTime类型的值可以有多种形式,如described in RELAX NG

如何将所有表单解析为时间或日期时间对象?

2 个答案:

答案 0 :(得分:2)

它实际上是一种非常受限制的格式,特别是与所有ISO 8601相比。使用正则表达式与使用strptime和自己处理偏移量(strptime不这样做)大致相同。

import datetime
import re

def parse_timestamp(s):
  """Returns (datetime, tz offset in minutes) or (None, None)."""
  m = re.match(""" ^
    (?P<year>-?[0-9]{4}) - (?P<month>[0-9]{2}) - (?P<day>[0-9]{2})
    T (?P<hour>[0-9]{2}) : (?P<minute>[0-9]{2}) : (?P<second>[0-9]{2})
    (?P<microsecond>\.[0-9]{1,6})?
    (?P<tz>
      Z | (?P<tz_hr>[-+][0-9]{2}) : (?P<tz_min>[0-9]{2})
    )?
    $ """, s, re.X)
  if m is not None:
    values = m.groupdict()
    if values["tz"] in ("Z", None):
      tz = 0
    else:
      tz = int(values["tz_hr"]) * 60 + int(values["tz_min"])
    if values["microsecond"] is None:
      values["microsecond"] = 0
    else:
      values["microsecond"] = values["microsecond"][1:]
      values["microsecond"] += "0" * (6 - len(values["microsecond"]))
    values = dict((k, int(v)) for k, v in values.iteritems()
                  if not k.startswith("tz"))
    try:
      return datetime.datetime(**values), tz
    except ValueError:
      pass
  return None, None

不处理将时区偏移应用于日期时间,而负数年是日期时间的问题。这两个问题都可以通过处理xsd:dateTime所需的完整范围的不同时间戳类型来修复。

valid = [
  "2001-10-26T21:32:52",
  "2001-10-26T21:32:52+02:00",
  "2001-10-26T19:32:52Z",
  "2001-10-26T19:32:52+00:00",
  #"-2001-10-26T21:32:52",
  "2001-10-26T21:32:52.12679",
]
for v in valid:
  print
  print v
  r = parse_timestamp(v)
  assert all(x is not None for x in r), v

  # quick and dirty, and slightly wrong
  # (doesn't distinguish +00:00 from Z among other issues)
  # but gets through the above cases

  tz = ":".join("%02d" % x for x in divmod(r[1], 60)) if r[1] else "Z"
  if r[1] > 0: tz = "+" + tz
  r = r[0].isoformat() + tz

  print r
  assert r.startswith(v[:len("CCYY-MM-DDThh:mm:ss")]), v

print "---"
invalid = [
  "2001-10-26",
  "2001-10-26T21:32",
  "2001-10-26T25:32:52+02:00",
  "01-10-26T21:32",
]
for v in invalid:
  print v
  r = parse_timestamp(v)
  assert all(x is None for x in r), v

答案 1 :(得分:1)

尝试python-dateutil中的dateutil.parser模块。或许isodate(尚未使用最后一个,但看起来很有趣(并且专门用于解析ISO 8601格式)。