Question

我将此作为来自服务器的Web响应，我想解析它并将其添加到列表中

{
    "Id": [
        "7",
        "8",
        "9"
    ],
    "Title": [
        "Title 1",
        "Title 2",
        "Title 3"
    ],
    "Description": [
        "desc1",
        "desc2",
        "desc3"
    ],
    "NewsUpdatedDateTime": [
        "2010-02-26T10:40:30",
        "2010-02-27T10:40:30",
        "2010-02-28T10:40:30"
    ],
    "ImageUrl": [
        "image1.jpg",
        "image2.jpg",
        "image3.jpg"
    ],
    "LastUpdatedTime": "2010-02-28T10:40:30",
    "ResponseMessage": "Data retrieved successfully",
    "ResponseCode": "1"
}

Answer 1

关注this进行JSON解析...

我为您的JSON数据创建示例代码。检查并告诉我它是否正常工作？

String jsonData = your_data;
ArrayList<String> mListID;
ArrayList<String> mListTitle;

try {
JSONObject jsonOBJ = new JSONObject(jsonData);

// Getting JSON Array node
JSONArray mArrayID  =  jsonObj.getJSONArray("ID");
mListID = new ArrayList<String>();

for(int i=0 ; i<mArrayId.length(); i++)
{
    mListID.add(mArrayId.get(i))
}
JSONArray mArrayTitle  =  jsonObj.getJSONArray("Title");
mListTitle = new ArrayList<String>();
for(int j=0 ; j<mArrayTitle.length(); j++)
{
    mListTitle.add(mArrayTitle.get(j))
}
} catch (JSONException e) {
   e.printStackTrace();
}

Answer 2

试试这个：

  //your json String
  String jsonStr;

  if (jsonStr != null) {
        try {
        JSONObject jsonObj = new JSONObject(jsonStr);

        // Getting JSON Array node
        JSONArray data  =  jsonObj.getJSONArray("ID");

        } catch (JSONException e) {
           e.printStackTrace();
        }
  }

你应该从here，here和here阅读一些关于android中json解析的教程和文档。

Answer 3

  You can implement it like this :



    List id;
    List title;
    String jsonTxt = inputStream;
    JSONObject jsonObj = new JSONObject(jsonTxt);
    JSONArray jsonArray1 = jsonObj.optJSONArray("Id");
    JSONArray jsonArray2 = jsonObj.optJSONArray("Title");
    if (jsonArray1.length() > 0) {
    id=new ArrayList();
    for (int index = 0; index < jsonArray1.length(); index++) {
    JSONObject sellerObj = jsonArray1.optJSONObject(index);
    id.add(sellerObj.optString("name"));//name of ids 
    }
   }

saee作为标题或其他数组。

Answer 4

首先解析服务器响应

json jsonResponse = new json(response);

JSONArray id[] = jsonResponse.getJSONArray("Id");

JSONArray title = jsonResponse.getJSONArray("Title");

JSONArray description[] = jsonResponse.getJSONArray("Description");

JSONArray newsUpdatedDateTime[] = jsonResponse.getJSONArray("NewsUpdatedDateTime");

JSONArray imageUrl[] = jsonResponse.getJSONArray("ImageUrl");

String lastUpdateTime =  jsonResponse.getString("LastUpdatedTime");

String responseMessage =  jsonResponse.getString("ResponseMessage");

String responseCode =  jsonResponse.getString("ResponseCode");

// ============================================= ============================= //

然后你可以解析仍然是你的单个数组：

    for (int i = 0; i < id.length(); i++) {  // **line 2**
     String name = id.get(i);
    }

我认为这会有所帮助。

使用多个数组解析Json对象并添加到列表中

4 个答案: