Question

我的嵌套循环只打印一个char，'c'，这是要打印的正确的第一个char，但我无法弄清楚为什么我的循环不会在字母表中循环。确定我的循环错误的任何帮助都会很棒。

#include <stdio.h>
#include <stdlib.h>

void problem_1_function();

int main(){

    problem_1_function();
    return (0);

}

void problem_1_function(){

    FILE *the_cipher_file;
    the_cipher_file = fopen("cipher.txt", "r");
    FILE *the_message_file;
    the_message_file = fopen("message.txt", "r");
    FILE * the_decode_file;
    the_decode_file = fopen("decode.txt", "w");
    int the_letter_counter = 0;
    int the_alphabet_array[100];
    int size_of_alphabet = 0;
    int size_of_message = 0;
    int the_message_counter = 0;
    int the_message_array[100];
    char the_decode_array [15];
    char the_letter_char[26] = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','w','x','y','z'};

    if(the_decode_file == NULL){
            printf("Error opening file!\n");
}
    if(!the_cipher_file){
            printf("Error: Filename \"cipher.txt\" not found!\n");
    }

     while(fscanf(the_cipher_file, " %d%*[,] ", &size_of_alphabet) > 0 && the_letter_counter < 100){
            the_alphabet_array[the_letter_counter] = size_of_alphabet;
            //printf("%d ", size_of_alphabet);
            the_letter_counter++;
            }

    if(!the_message_file){
            printf("Error: Filename \"cipher.txt\" not found!\n");
    }
    while(fscanf(the_message_file, " %d%*[,] ", &size_of_message) > 0 && the_message_counter < 100){
            the_message_array[the_message_counter] = size_of_message;
            //printf("%d ", size_of_message);
            the_message_counter++;
}
    int message_equals_cipher = 0;
    int message_equals_cipher2 = 0;

    for(message_equals_cipher; message_equals_cipher < sizeof(the_message_array); message_equals_cipher++){      //these nested loops go through the alphabet to print letters corresponding to arrays...
            for(message_equals_cipher2; message_equals_cipher2 < 26; message_equals_cipher2++){
                    if(the_message_array[message_equals_cipher] == the_alphabet_array[message_equals_cipher2]){
                            the_decode_array[message_equals_cipher] = the_letter_char[message_equals_cipher2];
                            fprintf(the_decode_file, "%c", the_decode_array[message_equals_cipher]);
                    }
            }
    }

    fclose(the_cipher_file);
    fclose(the_message_file);
    fclose(the_decode_file);
}

Answer 1

int message_equals_cipher = 0;
int message_equals_cipher2 = 0;

for(message_equals_cipher; ...
    for(message_equals_cipher2; ...

你在循环之外将它们设置为0 ..你的for语句的初始化表达式什么都不做 - 如果你将警告级别设置得足够高，你的编译器应该告诉你。因为你没有重置message_equals_cipher2，你的内部循环只会运行一次。你想要

for(message_equals_cipher = 0; ...
    for(message_equals_cipher2 = 0; ...

如果您正在编译C99或更高版本，则可以执行

for(int message_equals_cipher = 0; ...
    for(int message_equals_cipher2 = 0; ...

并摆脱先前对这些变量的定义。

Answer 2

是的，嵌套for循环中的问题是您未在第二个message_equals_cipher2循环中将0变量初始化为for。嵌套代码应该是：

  for(message_equals_cipher; message_equals_cipher < sizeof(the_message_array); message_equals_cipher++)
  {
      for(message_equals_cipher2=0; message_equals_cipher2 < 26; message_equals_cipher2++)
      {
                     // Your stuff
      }
  }

我同意jim，而不是在嵌套message_equals_cipher循环之前初始化变量message_equals_cipher2和for。您可以按指定的jim进行操作。

C - 嵌套for循环不打印多个元素

2 个答案: