我一直在寻找年龄而且我再次陷入困境,当我为与数据库中的密码匹配的用户输入正确的密码时,我的代码没有回应“ok”。
其他一切都很好,我不确定我是否错过了任何愚蠢的事情;我可能有,为愚蠢道歉:)
PHP:
class User {
private $_db, $data;
public function __construct($user = null) {
$this->_db = DB::getInstance();
}
public function create($fields = array()) {
if(!$this->_db->insert('users', $fields)) {
throw new Exception('There was a problem registering');
}
}
public function find($user = null) {
if($user) {
$field = (is_numeric($user)) ? 'id' : 'username';
$data = $this->_db->get('users', array($field, '=', $user));
if($data->count()) {
$this->_data = $data->first();
return true;
}
}
return false;
}
public function login($username = null, $password = null) {
$user = $this->find($username);
if($user) {
if($this->data()->password === Hash::make($password, $this->data()->salt)) {
echo 'ok';
}
}
return false;
}
private function data() {
return $this->_data;
}
}
答案 0 :(得分:1)
在你的login()
上,你必须像这样重写......
public function login($username = null, $password = null) {
$user = $this->find($username);
if($user) {
if($this->data()->password === Hash::make($password, $this->data()->salt)) {
//echo 'ok';
return true;
}
}
else { return false; }
}
注释掉echo
并从那里返回true。所以你将从你的实例中调用你的函数,比如
if($someinst->find('someuser'))
{
echo "User Found";
}
else { echo "Not Found"; }
答案 1 :(得分:1)
尝试这样来解决您的问题:
public function login($username = null, $password = null)
{
$user = $this->find($username);
if($user) {
if($this->data()->password === Hash::make($password, $this->data()->salt)) {
echo 'User and password Ok!';
} else {
echo 'User and password do not match'; // Handle it
}
} else {
echo 'User not found'; // Handle it
}
return false;
}
此外,在第一种观点,这可能是问题:
$this->data()->password
也许你应该使用类似的东西:
if($user->password === Hash::make($password ...