Question

我有一个简单的表单，如下所示：

@using (Html.BeginForm("search", "home", new { param1 = "value1" }, FormMethod.Get ))
{
     @Html.TextBox("Search", ViewBag.Search as string)
     <button type="submit">Search </button>
}

HTML输出如下所示：

 <form action="/home/search?param1=value1" method="get">  
     <input id="Search" name="Search" type="text" value="">
     <button type="submit">Search </button>
 </form>

和我的控制器看起来像这样：

public ActionResult Search(string param1, string search)  
{
    // param1 returns as "null" 
    // search contains the value that was inside the textbox
}

有人知道我做错了什么吗？

Answer 1

一些建议

使用带有POST的表单
我总是建议使用强类型视图模型，它有很多好处

所以你的代码变成了：

public class SearchViewModel {
    public string param1 {get;set;}
    public string search {get;set;}
}

[HttpPost] // <-- were you missing this before?
public ActionResult Search(SearchViewModel model)  
{
   // access with model.param1
}

@model SearchViewModel

@using (Html.BeginForm("search", "home", FormMethod.POST ))
{
     @Html.HiddenFor(x=>x.param1)
     @Html.TextBoxFor(x=>x.search)
     <button type="submit">Search </button>
}

Answer 2

Selman22提出了实现这一目标的正确方法。您可以将它们放在隐藏的表单中，而不是将params放在实际的URL上。

@using (Html.BeginForm("search", "home", null, FormMethod.Get ))
{
     <input type="hidden" name="param1" value="@ViewBag.Param1Value.ToString()" /> 
     @Html.TextBox("Search", ViewBag.Search as string)
     <button type="submit">Search </button>
}

谢谢!!!!

Html.BeginForm不带有当前的参数

2 个答案: