我遇到麻烦,返回“T”类型的值。展示比解释更容易,所以这里是方法:
Protected Function GetElementValue(Of T)(ByVal nodeName As String, Optional missingIfNotExists As Boolean = True,
Optional missingIfEmpty As Boolean = True,
Optional ByRef defaultVal As T = Nothing,
Optional maxLength As Integer = Nothing) As T
'Set up the node to get the value from
Dim node = xmlRoot.SelectSingleNode(nodeName)
Select Case True
Case IsNothing(node) 'If the node is missing from the xml document
'Add the node to the misssing elements array if missingIfNotExists = True
If missingIfNotExists Then missingElements.Add(nodeName)
'Return the default value
Return defaultVal
Case node.InnerText.Trim.Length = 0 'The node exists in the xml document but has no value
'Add it to missing elements if missingIfEmpty = True
If missingIfEmpty Then missingElements.Add(nodeName)
'If there is a default value passed in, return that value
Return defaultVal
Case Else 'The node exists and contains data
End Select
'The element exists and contains data
Dim nodeValue = node.InnerText.Trim
'If a size constraint was passed in, ensure the element data is not too long. Shorten the string if it is
If Not IsNothing(maxLength) AndAlso nodeValue.Length > maxLength Then nodeValue = nodeValue.Substring(0, maxLength)
Return CType(nodeValue, T)
End Function
有任何想法或建议吗?
感谢。
最后一次回归是我遇到问题的地方。它说“nodeValue无法转换为T型”
我尝试了以下方案并得到错误:“类型整数的值不能转换为类型T”:
Select Case defaultVal.GetType()
Case GetType(Integer)
Return CType(nodeValue, Integer)
End Select
答案 0 :(得分:3)
如果您之前将值存储为对象,则可以:
Sub Main()
Dim myInt = Foo(Of Integer)("123")
End Sub
Function Foo(Of T)(input As String) As T
Dim bar As Object = input
Return CType(bar, T)
End Function