Question

我正在制作一个预订系统，因此我需要能够在让用户预订之前检查时隙是否可用（我的功能还会在检查前后添加1个时间段来覆盖旅行时间等）。 / p>

function timeSlotAvailable($date, $time){

    $timeslots = array($time - 1, $time, $time + 1);
    $slots = join(',',$timeslots); 

    $STH = $this->database->prepare("SELECT COUNT(*) FROM bookings WHERE bookings.date = :bdate AND bookings.slot IN (:ids)");
    $STH->execute(array(":bdate"=>$date, ":ids"=>$slots));
    $data = $STH->fetchColumn();
    return "checking date:".$date." for slots ".$slots." the count is ".$data;

}

输出

checking date:02/15/2014 for slots 3,4,5 the count is 0

现在在bookings时间槽4上有一个用于该日期的插槽。然后我在phpmyadmin中尝试此查询

SELECT COUNT(*) FROM bookings WHERE bookings.date = "02/15/2014" AND bookings.slot IN (3,4,5)

本质上是相同的查询（提交相同的变量），但返回的1响应正确。这让我觉得我的代码有些问题是我看不到的。

Answer 1

问题在于：

function timeSlotAvailable($date, $time){

$timeslots = array($time - 1, $time, $time + 1); 
$slots = join(',',$timeslots); //bad

$STH = $this->database->prepare("SELECT COUNT(*) FROM bookings WHERE bookings.date = :bdate AND bookings.slot IN (:ids)");
$STH->execute(array(":bdate"=>$date, ":ids"=>$slots)); //here is the problem
$data = $STH->fetchColumn();
return "checking date:".$date." for slots ".$slots." the count is ".$data;

}

这样您的查询就像：

SELECT COUNT(*) 
FROM bookings WHERE bookings.date ='02/15/2014' 
AND bookings.slot IN (3) //Just took one, oops

当然答案是零。

以这种方式更改您的代码：

function timeSlotAvailable($date, $time){

$timeslots = array($time - 1, $time, $time + 1); 

$STH = $this->database->prepare("SELECT COUNT(*) FROM bookings WHERE bookings.date = :bdate AND bookings.slot IN (:ids)");
$STH->execute(array(":bdate"=>$date, ":ids"=>$timeslots)); 
$data = $STH->fetchColumn();
return "checking date:".$date." for slots ".$slots." the count is ".$data;

}

或者这样：

function timeSlotAvailable($date, $time){

$timeslots = array($time - 1, $time, $time + 1); 
$slots = join(',',$timeslots); 

$STH = $this->database->prepare("SELECT COUNT(*) FROM bookings WHERE bookings.date = :bdate AND bookings.slot IN (".$slots.")");
$STH->execute(array(":bdate"=>$date)); 
$data = $STH->fetchColumn();
return "checking date:".$date." for slots ".$slots." the count is ".$data;

}

查询在phpmyadmin中工作，但不在脚本中

1 个答案: