我有一个场景,其中我有一个类Resource,其中有两个嵌套在其中的类; Action和ResourceURL。我需要为Resource和Action编写自定义xmlserializer,而不是为ResourceURL编写。我为两者实现了IXmlSerializable。
问题是,当Resource被序列化时,我调用Action.WriteXML(XmlWriter)来获取Action的序列化形式,但是我无法获得ResourceURL的序列化形式。标签变得混乱,并且还添加了标签。
那么我如何序列化一个对某些嵌套对象进行客户seril化而不为其他对象进行sercel化的对象呢?
答案 0 :(得分:19)
以下是WriteXml方法示例:
void IXmlSerializable.WriteXml(XmlWriter writer)
{
// Simple string value:
writer.WriteAttributeString("Name", this.Name);
// Object without IXmlSerializable implementation:
writer.WriteStartElement("NonCustomObject");
new XmlSerializer(NonCustomObjectType).Serialize(writer, this.NonCustomObject);
writer.WriteEndElement();
// Object with IXmlSerializable implementation:
writer.WriteStartElement("CustomObject");
(this.CustomObject as IXmlSerializable).WriteXml(writer);
writer.WriteEndElement();
}
这是一个相应的ReadXml方法:
void IXmlSerializable.ReadXml(XmlReader reader)
{
// Simple string value
this.Name = reader.GetAttribute("Name");
// Object without IXmlSerializable implementation here:
reader.ReadStartElement();
if (reader.Name == "NonCustomObject")
{
reader.ReadStartElement();
this.NonCustomObject = new XmlSerializer(NonCustomObjectType).Deserialize(reader);
reader.ReadEndElement();
}
// Object with IXmlSerializable implementation here:
reader.ReadStartElement();
if (reader.Name == "CustomObject")
{
(this.CustomObject as IXmlSerializable).ReadXml(reader);
reader.ReadEndElement();
}
}