我正在使用GoogleMap API在GoogleMap上显示两点之间的绘制方向。
我想在iOS 6.1上给予支持,所以我使用GoogleMap,我知道iOS7可以恢复它。
使用下面的代码进行解析并获取坐标的步骤以在地图上绘制折线:
NSString *str=@"http://maps.googleapis.com/maps/api/directions/json?origin=bharuch,gujarat&destination=vadodara,gujarat&sensor=false";
NSURL *url=[[NSURL alloc]initWithString:[str stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];
NSURLRequest *request = [NSURLRequest requestWithURL:url cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0];
NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
NSError* error;
NSDictionary* json = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
NSArray* latestRoutes = [json objectForKey:@"routes"];
NSMutableDictionary *legs=[[[latestRoutes objectAtIndex:0] objectForKey:@"legs"] objectAtIndex:0];
NSArray *steps=[legs objectForKey:@"steps"];
NSString *startLocation,*endLocation,*totalDistance,*totalDuration;
CLLocationCoordinate2D startLoc,endLoc;
startLocation = [legs objectForKey:@"start_address"];
endLocation = [legs objectForKey:@"end_address"];
totalDistance = [[legs objectForKey:@"distance"] objectForKey:@"text"];
totalDuration = [[legs objectForKey:@"duration"] objectForKey:@"text"];
startLoc=CLLocationCoordinate2DMake([[[legs objectForKey:@"start_location"] objectForKey:@"lat"] doubleValue], [[[legs objectForKey:@"start_location"] objectForKey:@"lng"] doubleValue]);
endLoc=CLLocationCoordinate2DMake([[[legs objectForKey:@"end_location"] objectForKey:@"lat"] doubleValue], [[[legs objectForKey:@"end_location"] objectForKey:@"lng"] doubleValue]);
NSMutableDictionary *tempDict;
if ([steps count]!=0) {
GMSMutablePath *path = [GMSMutablePath path];
for(int idx = 0; idx < [steps count]+2; idx++){
CLLocationCoordinate2D workingCoordinate;
if (idx==0) {
workingCoordinate=startLoc;
[path addCoordinate:workingCoordinate];
}
else if (idx==[steps count]+1){
workingCoordinate=endLoc;
[path addCoordinate:workingCoordinate];
}
else{
workingCoordinate=CLLocationCoordinate2DMake([[[[steps objectAtIndex:idx-1] objectForKey:@"start_location"] objectForKey:@"lat"] floatValue], [[[[steps objectAtIndex:idx-1] objectForKey:@"start_location"] objectForKey:@"lng"] floatValue]);
[path addCoordinate:workingCoordinate];
}
tempDict = nil;
}
// create the polyline based on the array of points.
GMSPolyline *rectangle = [GMSPolyline polylineWithPath:path];
rectangle.strokeWidth=5.0;
rectangle.map = mapView_;
}
它只给出24个步骤意味着只有24个坐标用于创建点并在地图上绘制线条,如下图所示:
你可以看到该线路不在正确的路上,那么我该怎么做才能解决这个问题呢? 我也想在地图上显示方向。
答案 0 :(得分:8)
以下答案是在@ABáo的帮助下,两个位置之间的平滑路径:
-(void)viewDidLoad { // Create a GMSCameraPosition that tells the map to display the GMSCameraPosition *camera = [GMSCameraPosition cameraWithLatitude:21.718472 longitude:73.030422 zoom:6]; mapView_ = [GMSMapView mapWithFrame:CGRectZero camera:camera]; mapView_.delegate=self; mapView_.myLocationEnabled = YES; mapView_.settings.myLocationButton=YES; mapView_.settings.indoorPicker=NO; mapView_.settings.compassButton=YES; self.view = mapView_; NSString *str=@"http://maps.googleapis.com/maps/api/directions/json?origin=Bharuch,gujarat&destination=vadodara,gujarat&sensor=false"; NSURL *url=[[NSURL alloc]initWithString:[str stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]]; NSURLRequest *request = [NSURLRequest requestWithURL:url cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0]; NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil]; NSError* error; NSDictionary* json = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error]; NSArray* latestRoutes = [json objectForKey:@"routes"]; NSString *points=[[[latestRoutes objectAtIndex:0] objectForKey:@"overview_polyline"] objectForKey:@"points"]; @try { // TODO: better parsing. Regular expression? NSArray *temp= [self decodePolyLine:[points mutableCopy]]; GMSMutablePath *path = [GMSMutablePath path]; for(int idx = 0; idx < [temp count]; idx++) { CLLocation *location=[temp objectAtIndex:idx]; [path addCoordinate:location.coordinate]; } // create the polyline based on the array of points. GMSPolyline *rectangle = [GMSPolyline polylineWithPath:path]; rectangle.strokeWidth=5.0; rectangle.map = mapView_; } @catch (NSException * e) { // TODO: show error } } -(NSMutableArray *)decodePolyLine: (NSMutableString *)encoded { [encoded replaceOccurrencesOfString:@"\\\\" withString:@"\\" options:NSLiteralSearch range:NSMakeRange(0, [encoded length])]; NSInteger len = [encoded length]; NSInteger index = 0; NSMutableArray *array = [[NSMutableArray alloc] init] ; NSInteger lat=0; NSInteger lng=0; while (index < len) { NSInteger b; NSInteger shift = 0; NSInteger result = 0; do { b = [encoded characterAtIndex:index++] - 63; result |= (b & 0x1f) << shift; shift += 5; } while (b >= 0x20); NSInteger dlat = ((result & 1) ? ~(result >> 1) : (result >> 1)); lat += dlat; shift = 0; result = 0; do { b = [encoded characterAtIndex:index++] - 63; result |= (b & 0x1f) << shift; shift += 5; } while (b >= 0x20); NSInteger dlng = ((result & 1) ? ~(result >> 1) : (result >> 1)); lng += dlng; NSNumber *latitude = [[NSNumber alloc] initWithFloat:lat * 1e-5] ; NSNumber *longitude = [[NSNumber alloc] initWithFloat:lng * 1e-5] ; printf("[%f,", [latitude doubleValue]); printf("%f]", [longitude doubleValue]); CLLocation *loc = [[CLLocation alloc] initWithLatitude:[latitude floatValue] longitude:[longitude floatValue]] ; [array addObject:loc]; } return array; }
此代码的屏幕截图,您可以将它与之前用于询问的屏幕截图进行比较问题:
答案 1 :(得分:1)
我确实将GMSMarker添加到每个点上的步骤数组,我确定使用步骤数组start_location和end_location不足以在地图中显示方向。这是我从您的代码中编辑的代码
NSString *str=@"http://maps.googleapis.com/maps/api/directions/json?origin=bharuch,gujarat&destination=vadodara,gujarat&sensor=false";
NSURL *url=[[NSURL alloc]initWithString:[str stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];
NSURLRequest *request = [NSURLRequest requestWithURL:url cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0];
NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
NSError *error;
NSDictionary* json = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
NSArray* latestRoutes = [json objectForKey:@"routes"];
NSMutableDictionary *legs=[[[latestRoutes objectAtIndex:0] objectForKey:@"legs"] objectAtIndex:0];
NSArray *steps=[legs objectForKey:@"steps"];
NSString *startLocation,*endLocation,*totalDistance,*totalDuration;
CLLocationCoordinate2D startLoc,endLoc;
startLocation = [legs objectForKey:@"start_address"];
endLocation = [legs objectForKey:@"end_address"];
totalDistance = [[legs objectForKey:@"distance"] objectForKey:@"text"];
totalDuration = [[legs objectForKey:@"duration"] objectForKey:@"text"];
startLoc=CLLocationCoordinate2DMake([[[legs objectForKey:@"start_location"] objectForKey:@"lat"] doubleValue], [[[legs objectForKey:@"start_location"] objectForKey:@"lng"] doubleValue]);
NSMutableDictionary *stopLegs=[[[latestRoutes objectAtIndex:0] objectForKey:@"legs"] objectAtIndex:0];
endLoc=CLLocationCoordinate2DMake([[[stopLegs objectForKey:@"end_location"] objectForKey:@"lat"] doubleValue], [[[stopLegs objectForKey:@"end_location"] objectForKey:@"lng"] doubleValue]);
NSMutableDictionary *tempDict;
if ([steps count]!=0) {
// add marker
NSDictionary *step;
for (int i= 0; i < steps.count; i++) {
step = [steps objectAtIndex:i];
NSDictionary *location = [step objectForKey:@"start_location"];
double lat = [[location objectForKey:@"lat"] doubleValue];
double lng = [[location objectForKey:@"lng"] doubleValue];
GMSMarker *marker = [[GMSMarker alloc] init];
marker.position = CLLocationCoordinate2DMake(lat, lng);
marker.snippet = [NSString stringWithFormat:@"point (%d)", i+1];
marker.map = mapView_;
}
NSDictionary *location = [step objectForKey:@"end_location"];
double lat = [[location objectForKey:@"lat"] doubleValue];
double lng = [[location objectForKey:@"lng"] doubleValue];
GMSMarker *marker = [[GMSMarker alloc] init];
marker.position = CLLocationCoordinate2DMake(lat, lng);
marker.snippet = [NSString stringWithFormat:@"point (%d)", steps.count];
marker.map = mapView_;
// continue draw map
GMSMutablePath *path = [GMSMutablePath path];
for(int idx = 0; idx < [steps count]+2; idx++){
CLLocationCoordinate2D workingCoordinate;
if (idx==0) {
workingCoordinate=startLoc;
[path addCoordinate:workingCoordinate];
}
else if (idx==[steps count]+1){
workingCoordinate=endLoc;
[path addCoordinate:workingCoordinate];
}
else{
workingCoordinate=CLLocationCoordinate2DMake([[[[steps objectAtIndex:idx-1] objectForKey:@"start_location"] objectForKey:@"lat"] floatValue], [[[[steps objectAtIndex:idx-1] objectForKey:@"start_location"] objectForKey:@"lng"] floatValue]);
[path addCoordinate:workingCoordinate];
}
tempDict = nil;
}
// create the polyline based on the array of points.
GMSPolyline *rectangle = [GMSPolyline polylineWithPath:path];
rectangle.strokeWidth=5.0;
rectangle.map = mapView_;
}
你可以看到第12点和第13点之间的距离很远(60.2公里)。但它只是一条路。我确实发现,如果你想显示结果方向的近似(平滑)路径。你需要使用“overview_polyline”字段。 overview_polyline:包含一个包含编码点数组的对象,这些编码点表示结果方向的近似(平滑)路径。这个link google map develop对你有帮助。因此,为您工作的是找到从“overview_polyline”解码数据的方法,以获得两点之间的正确路径。我绝对是解决问题的真正方法,因为我确实在Encoded Polyline Algorithm Format检查工具以解码“overview_polyline” 这张图片是我从解码中得到的:
要解码多边形字符串,您可以在此块http://objc.id.au/post/9245961184/mapkit-encoded-polylines
找到-(void)viewDidLoad { // Create a GMSCameraPosition that tells the map to display the GMSCameraPosition *camera = [GMSCameraPosition cameraWithLatitude:21.718472 longitude:73.030422 zoom:6]; mapView_ = [GMSMapView mapWithFrame:CGRectZero camera:camera]; mapView_.delegate=self; mapView_.myLocationEnabled = YES; mapView_.settings.myLocationButton=YES; mapView_.settings.indoorPicker=NO; mapView_.settings.compassButton=YES; self.view = mapView_; NSString *str=@"http://maps.googleapis.com/maps/api/directions/json?origin=Bharuch,gujarat&destination=vadodara,gujarat&sensor=false"; NSURL *url=[[NSURL alloc]initWithString:[str stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]]; NSURLRequest *request = [NSURLRequest requestWithURL:url cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0]; NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil]; NSError* error; NSDictionary* json = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error]; NSArray* latestRoutes = [json objectForKey:@"routes"]; NSString *points=[[[latestRoutes objectAtIndex:0] objectForKey:@"overview_polyline"] objectForKey:@"points"]; @try { // TODO: better parsing. Regular expression? NSArray *temp= [self decodePolyLine:[points mutableCopy]]; GMSMutablePath *path = [GMSMutablePath path]; for(int idx = 0; idx < [temp count]; idx++) { CLLocation *location=[temp objectAtIndex:idx]; [path addCoordinate:location.coordinate]; } // create the polyline based on the array of points. GMSPolyline *rectangle = [GMSPolyline polylineWithPath:path]; rectangle.strokeWidth=5.0; rectangle.map = mapView_; } @catch (NSException * e) { // TODO: show error } } -(NSMutableArray *)decodePolyLine: (NSMutableString *)encoded { [encoded replaceOccurrencesOfString:@"\\\\" withString:@"\\" options:NSLiteralSearch range:NSMakeRange(0, [encoded length])]; NSInteger len = [encoded length]; NSInteger index = 0; NSMutableArray *array = [[NSMutableArray alloc] init] ; NSInteger lat=0; NSInteger lng=0; while (index < len) { NSInteger b; NSInteger shift = 0; NSInteger result = 0; do { b = [encoded characterAtIndex:index++] - 63; result |= (b & 0x1f) << shift; shift += 5; } while (b >= 0x20); NSInteger dlat = ((result & 1) ? ~(result >> 1) : (result >> 1)); lat += dlat; shift = 0; result = 0; do { b = [encoded characterAtIndex:index++] - 63; result |= (b & 0x1f) << shift; shift += 5; } while (b >= 0x20); NSInteger dlng = ((result & 1) ? ~(result >> 1) : (result >> 1)); lng += dlng; NSNumber *latitude = [[NSNumber alloc] initWithFloat:lat * 1e-5] ; NSNumber *longitude = [[NSNumber alloc] initWithFloat:lng * 1e-5] ; printf("[%f,", [latitude doubleValue]); printf("%f]", [longitude doubleValue]); CLLocation *loc = [[CLLocation alloc] initWithLatitude:[latitude floatValue] longitude:[longitude floatValue]] ; [array addObject:loc]; } return array; }
此代码的屏幕截图,您可以将它与之前用于询问的屏幕截图进行比较问题:
谢谢@jayraj m.g。