Question

环境：Scala 2.10+ IDE：Eclipse Kepler

我有一条线 NAME=bala AGE=23 COUNTRY=Singapore

如何将其作为地图

Map(NAME -> bala, AGE -> 23, COUNTRY -> Singapore)

Answer 1

另一种解决方案

val str = "NAME=bala AGE=23 COUNTRY=Singapore"
val pairs = str.split("=| ").grouped(2)
val map = pairs.map { case Array(k, v) => k -> v }.toMap
// Map(NAME -> bala, AGE -> 23, COUNTRY -> Singapore)

Answer 2

我想到了这样的事情，但我几乎肯定有一种更有效的方式：

val line = "NAME=bala AGE=23 COUNTRY=Singapore"
line.split(" ").map(_.split("=")).map(arr => arr(0) -> arr(1)).toMap

这给了我：

res10: scala.collection.immutable.Map[String,String] = Map(NAME -> bala, AGE -> 23, COUNTRY -> Singapore)

Answer 3

使用正则表达式：

val line = "NAME=bala AGE=23 COUNTRY=Singapore"

val regex = """(\w+)=(\w+)""".r
val map = line.split("\\s+") map { elem =>
  val regex(key, value) = elem
  (key, value)
} toMap

Scala：如何将String拆分为Map

3 个答案: