Question

class Program
{
    static void Main(string[] args)
    {
        string s = "Stack Overflows";

        var x = from c in s.ToLower()
                group c by c into a
                select new { a.Key, Count = a.Count() };
        Console.WriteLine(Convert.ToString(x));

        Console.Read();
    }
}

输出为system.linq.Enumable +

i want output like a 2 g 1 s 1 p 2 r 1

Answer 1

Console.WriteLine(String.Join(" ", x.Select(y=>y.Key + " " + y.Count)));

或使用lambda语法

string s = "Stack Overflows";
Console.WriteLine(String.Join(" ", s.GroupBy(c => c)
                                    .Select(g => g.Key + " " + g.Count())));

Answer 2

你也可以使用这样的聚合函数：

Console.WriteLine(x.Select(y => String.Format("{0} {1}", y.Key, y.Count)).Aggregate((y, z) => y + String.Format(" {0}", z)));

Aggregate函数可用于任何类型（不仅仅是字符串）

Answer 3

尝试使用此代码而不是代码，我修改了@ L.B代码

string s = "Stack Overflows";    
 var x = String.Join("", (from c in s.ToLower()
         group c by c into a 
         select new { a.Key, Count = a.Count() }).Select(y => y.Key + " " + y.Count));

使用count打印字符串中的不同字符

3 个答案: