Question

//我需要创建以下XML。我搜索了很多，但无法理解如何创建这种类型的xml：

  <CommandInfoDTO ClassName="DomainDTO">
    <Domains>
      <a:string>kochar.com</a:string>
      <a:string>yahoo.com</a:string>
    </Domains>
  </CommandInfoDTO>

//我创建了具有单个节点的xml，因此我使用了JaxB和Marshaller

@XmlRootElement(name = "CommandInfoDTO")
@XmlAccessorType(XmlAccessType.FIELD)
public class EnforcePasswordDTO {

    @XmlAttribute(name = "ClassName")
    String className = "EnforcePasswordDTO";
    @XmlElement(name = "AllowSpecialCharacters")
    boolean AllowSpecialCharacters = false;
    @XmlElement(name = "ChangeFrequency")
    String changeFrequency = null;
   }

 JAXBContext jc = JAXBContext.newInstance(EnforcePasswordDTO.class);
 Marshaller marshaller = jc.createMarshaller();

<CommandInfoDTO ClassName="EnforcePasswordDTO">
    <AllowSpecialCharacters>true</AllowSpecialCharacters>
    <ChangeFrequency>5</ChangeFrequency>
</CommandInfoDTO>

//但是我如何创建具有冒号的xml并且还有节点数。

Answer 1

编组 - 没问题

要在元素名称中编组（输出）冒号（:），您只需在相应的JAXB注释的name参数中指定它。

@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
public class Foo {

    @XmlElement(name="notANamespacePrefix:bar")
    String bar;

}

<强>输出

<?xml version="1.0" encoding="UTF-8"?>
<foo>
    <notANamespacePrefix:bar>Hello World</notANamespacePrefix:bar>
</foo>

解组 - 需要特殊处理

无法胜任

如果您尝试在元素名称中解组包含冒号的XML，其中冒号前面的部分与命名空间前缀不对应，如下所示：

    Unmarshaller unmarshaller = jc.createUnmarshaller();
    File xml = new File("src/forum22088353/input.xml");
    Foo uFoo = (Foo) unmarshaller.unmarshal(xml);

然后你会得到如下例外：

Exception in thread "main" javax.xml.bind.UnmarshalException
 - with linked exception:
[org.xml.sax.SAXParseException; systemId: file:/Users/bdoughan/GIT/EclipseLink-Trunk3/Scratch/src/forum22088353/input.xml; lineNumber: 3; columnNumber: 30; The prefix "notANamespacePrefix" for element "notANamespacePrefix:bar" is not bound.]
    at javax.xml.bind.helpers.AbstractUnmarshallerImpl.createUnmarshalException(AbstractUnmarshallerImpl.java:335)
    at com.sun.xml.bind.v2.runtime.unmarshaller.UnmarshallerImpl.createUnmarshalException(UnmarshallerImpl.java:514)
    at com.sun.xml.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal0(UnmarshallerImpl.java:215)
    at com.sun.xml.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal(UnmarshallerImpl.java:184)
    at javax.xml.bind.helpers.AbstractUnmarshallerImpl.unmarshal(AbstractUnmarshallerImpl.java:157)
    at javax.xml.bind.helpers.AbstractUnmarshallerImpl.unmarshal(AbstractUnmarshallerImpl.java:162)
    at javax.xml.bind.helpers.AbstractUnmarshallerImpl.unmarshal(AbstractUnmarshallerImpl.java:171)
    at javax.xml.bind.helpers.AbstractUnmarshallerImpl.unmarshal(AbstractUnmarshallerImpl.java:189)
    at forum22088353.Demo.main(Demo.java:21)

将采取哪些措施

您可以将带有SAX的JAXB用于带冒号字符的属性进程元素名称。这是因为默认情况下，SAX解析器不支持名称空间。

    SAXParserFactory spf = SAXParserFactory.newInstance();
    SAXParser sp = spf.newSAXParser();
    XMLReader xmlReader = sp.getXMLReader();

    Unmarshaller unmarshaller = jc.createUnmarshaller();
    UnmarshallerHandler unmarshallerHandler = unmarshaller.getUnmarshallerHandler();
    xmlReader.setContentHandler(unmarshallerHandler);
    xmlReader.parse(new InputSource("src/forum22088353/input.xml"));
    Foo uFoo = (Foo) unmarshallerHandler.getResult();

如何创建允许Xml元素具有冒号和节点数的XML

1 个答案:

编组 - 没问题

解组 - 需要特殊处理